제출 #1306823

#제출 시각아이디문제언어결과실행 시간메모리
1306823Tymond코알라 (APIO17_koala)C++20
72 / 100
9 ms488 KiB
#include "koala.h" #include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; #define fi first #define se second #define vi vector<int> #define vll vector<long long> #define pii pair<int, int> #define pll pair<long long, long long> #define pb push_back #define mp make_pair #define eb emplace_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); mt19937_64 rng64(chrono::high_resolution_clock::now().time_since_epoch().count()); inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);} inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);} #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif int minValue(int N, int W) { int B[N]; for(int i = 0; i < N; i++){ B[i] = 0; } B[0] = 1; int X[N]; playRound(B, X); for(int i = 0; i < N; i++){ if(i == 0){ if(X[i] <= 1){ return i; } }else{ if(X[i] == 0){ return i; } } } return 0; } int maxValue(int N, int W) { int X[N]; vi vec = {}; for(int i = 0; i < N; i++){ vec.pb(i); } for(int j = 0; j < 4; j++){ int val = 1; while(sz(vec) * (val + 1) <= W && N > (val + 1) * (val + 2) / 2){ val++; } for(int i = 0; i < N; i++){ X[i] = 0; } for(auto ele : vec){ X[ele] = val; } int W[N]; playRound(X, W); vi nvec = {}; for(auto ele : vec){ if(W[ele] > X[ele]){ nvec.pb(ele); } } vec = nvec; //debug(vec); } return vec[0]; } int greaterValue(int N, int W) { // TODO: Implement Subtask 3 solution here. // You may leave this function unmodified if you are not attempting this // subtask. return 0; } const int MAXN = 107; int Val[MAXN][MAXN]; void calc(int N, int W){ for(int i = 1; i <= N; i++){ for(int j = i + 1; j <= N; j++){ for(int X = 1; X <= j / (j - i + 1); X++){ if(j > X * (X + 1) / 2 && i <= X * (j - i) + X * (X + 1) / 2){ Val[i][j] = X; } } } } } void f(int l, int p, vi vec, int *P, int N){ //cerr << l << ' ' << p << ' ' << Val[l][p] << '\n'; // debug(vec); if(l == p){ P[vec[0]] = l; return; } int X[N]; for(int i = 0; i < N; i++){ X[i] = 0; } for(auto ele : vec){ X[ele] = Val[l][p]; } // for(int j = 0; j < N; j++){ // cerr << X[j] << ' '; // } // cerr << '\n'; int W[N]; playRound(X, W); // for(int j = 0; j < N; j++){ // cerr << W[j] << ' '; // } // cerr << '\n'; vi big = {}; vi small = {}; for(auto ele : vec){ if(W[ele] > X[ele]){ big.pb(ele); }else{ small.pb(ele); } } f(l, l + sz(small) - 1, small, P, N); f(l + sz(small), p, big, P, N); } void allValues(int N, int W, int *P) { if(W == 2*N){ // TODO: Implement Subtask 4 solution here. // You may leave this block unmodified if you are not attempting this // subtask. }else{ vi vec = {}; for(int i = 0; i < N; i++){ vec.pb(i); } calc(N, W); f(1, N, vec, P, N); } }
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