//Proud of You//
#include <bits/stdc++.h>
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")
using namespace std;
const int N = 1e5 + 17;
int n, m, a[N], st[4 * N], lz[4 * N];
inline void build (int id, int l, int r)
{
if (l == r)
{
st[id] = a[l];
return;
}
int mid = (l + r) >> 1;
build (id * 2, l, mid);
build (id * 2 + 1, mid + 1, r);
st[id] = max (st[id * 2], st[id * 2 + 1]);
}
inline void down (int id)
{
if (lz[id] == 0) return;
st[id * 2] += lz[id];
lz[id * 2] += lz[id];
st[id * 2 + 1] += lz[id];
lz[id * 2 + 1] += lz[id];
lz[id] = 0;
}
inline void update (int id, int l, int r, int u, int v)
{
if (v < l || r < u)
{
return;
}
if (u <= l && r <= v)
{
++lz[id];
++st[id];
return;
}
int mid = (l + r) >> 1;
down(id);
update (id * 2, l, mid, u, v);
update (id * 2 + 1, mid + 1, r, u, v);
st[id] = max (st[id * 2], st[id * 2 + 1]);
}
inline int get (int id, int l, int r, int u)
{
if (u < l || u > r)
{
return 0;
}
if (l == r)
{
return st[id];
}
int mid = (l + r) >> 1;
down(id);
if (u <= mid) return get (id * 2, l, mid, u);
return get (id * 2 + 1, mid + 1, r, u);
}
inline int walk (int id, int l, int r, int z)
{
if (st[id] < z)
{
return n + 1;
}
if (l == r)
{
return l;
}
int mid = (l + r) >> 1;
down(id);
if (st[id * 2] >= z) return walk (id * 2, l, mid, z);
return walk (id * 2 + 1, mid + 1, r, z);
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> m;
for (int i = 1; i <= n; i++)
{
cin >> a[i];
}
sort (a + 1, a + n + 1);
build (1, 1, n);
while (m--)
{
char t;
int x, y;
cin >> t >> x >> y;
if (t == 'F')
{
int i = walk (1, 1, n, y);
if (i == n + 1) continue;
int need = x;
while (need > 0 && i <= n)
{
int val = get (1, 1, n, i);
int j = walk (1, 1, n, val + 1);
if (j == n + 1) j = n + 1;
int group_size = (j == n + 1 ? n + 1 - i : j - i);
if (group_size <= 0) break;
int take = min (group_size, need);
update (1, 1, n, i, i + take - 1);
need -= take;
i += take;
}
}
else
{
int l = walk (1, 1, n, x);
int r = walk (1, 1, n, y + 1);
int ans = r - l;
if (ans < 0) ans = 0;
if (l == n + 1) ans = 0;
cout << ans << "\n";
}
}
return 0;
}
