Submission #128057

#	Time	Username	Problem	Language	Result	Execution time	Memory
128057		ekrem	Sorting (IOI15_sorting)	C++98	0 / 100	5 ms	632 KiB

sorting

#include "sorting.h"
#include <bits/stdc++.h>
#define st first
#define nd second
#define mp make_pair
#define pb push_back
#define sol (k+k)
#define sag (k+k+1)
#define orta ((bas+son)/2)
#define coc g[node][i]
#define EKLE 1
#define mod 1000000007
#define inf 1000000009
#define MAXN 1000005
using namespace std;
 
typedef long long ll;
typedef pair < int , int > ii;
 
int n, m, f, a[MAXN], b[MAXN], x[MAXN], y[MAXN], yer[MAXN], p[MAXN], q[MAXN], s[MAXN], yerb[MAXN];
 
bool dene(int son){
 
	for(int i = 1; i <= n; i++)a[i] = s[i];
 
	for(int i = 1; i <= n; i++)
		b[i] = i;
 
	for(int i = son; i >= 1; i--)
		swap(b[x[i]], b[y[i]]);
 
	for(int i = 1; i <= n; i++){
		yer[a[i]] = i;
		yerb[b[i]] = i;
	}
 
	int su = 1;
	for(int i = 1; i <= son; i++){
		swap(a[x[i]], a[y[i]]);
		swap(yer[a[x[i]]], yer[a[y[i]]]);
		swap(b[x[i]], b[y[i]]);
		swap(yerb[b[x[i]]], yerb[b[y[i]]]);
		// cout << i << " ->\n";
		// for(int i = 1; i <= n; i++)cout << a[i] << " ";cout << endl;
		// for(int i = 1; i <= n; i++)cout << b[i] << " ";cout << endl;
		while(su <= n and yer[su] == yerb[su])
			su++;
		if(su > n){
			p[i] = q[i] = 1;
			continue;
		}
		int j = yer[su];
		p[i] = j;
		q[i] = yer[b[j]];
		swap(a[p[i]], a[q[i]]);
		swap(yer[a[p[i]]], yer[a[q[i]]]);
		su++;
 
	}
	// cout << son << " -> ";for(int i = 1; i <= n; i++)cout << a[i] << " ";cout << endl;
	for(int i = 1; i <= n; i++)
		if(a[i] != i)
			return 0;
	return 1;
}
 
int findSwapPairs(int nn, int S[], int M, int X[], int Y[], int P[], int Q[]) {n = nn;m = M;
	for(int i = 1; i <= n; i++){
		s[i] = a[i] = S[i - 1] + EKLE;
		if(a[i] != i)
			f = 1;
	}
	if(!f)return 0;
	for(int i = 1; i <= m; i++){
		x[i] = X[i - 1] + EKLE;
		y[i] = Y[i - 1] + EKLE;
	}
	int bas = 1, son = m;
	while(bas < son){
		if(dene(orta))
			son = orta;
		else
			bas = orta + 1;
	}
	dene(orta);
 
	for(int i = 1; i <= orta; i++){
		P[i - 1] = p[i] - EKLE;
		Q[i - 1] = q[i] - EKLE;
	}
	return orta;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 12
• Subtask 3: 0 / 16
• Subtask 4: 0 / 18
• Subtask 5: 0 / 20
• Subtask 6: 0 / 26