제출 #128030

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
128030		ekrem	정렬하기 (IOI15_sorting)	C++98	36 / 100	1067 ms	1200 KiB

sorting

#include "sorting.h"
#include <bits/stdc++.h>
#define st first
#define nd second
#define mp make_pair
#define pb push_back
#define sol (k+k)
#define sag (k+k+1)
#define orta ((bas+son)/2)
#define coc g[node][i]
#define EKLE 1
#define mod 1000000007
#define inf 1000000009
#define MAXN 1000005
using namespace std;

typedef long long ll;
typedef pair < int , int > ii;

int n, m, f, a[MAXN], b[MAXN], x[MAXN], y[MAXN], yer[MAXN], p[MAXN], q[MAXN], s[MAXN];
ii en[MAXN];

bool dene(int son){
	// cout << son << " -> ";
	for(int i = 1; i <= n; i++)a[i] = s[i];

	for(int i = 1; i <= n; i++)
		b[i] = i;
	for(int i = 1; i <= n; i++)
		en[i] = mp(0, i);
	for(int i = son; i >= 1; i--){
		en[x[i]].st = (!en[x[i]].st)?i:en[x[i]].st;
		en[y[i]].st = (!en[y[i]].st)?i:en[y[i]].st;
		swap(b[x[i]], b[y[i]]);
	// for(int i = 1; i <= n; i++)cout << b[i] << " ";cout << endl;

	}
	sort(en + 1, en + n + 1);
	for(int i = 1; i <= n; i++)
		yer[a[i]] = i;
	int su = 1;
	for(int i = 1; i <= son; i++){
		swap(a[x[i]], a[y[i]]);
		swap(yer[a[x[i]]], yer[a[y[i]]]);
		swap(b[x[i]], b[y[i]]);
		// cout << su << ":\n";
		// for(int i = 1; i <= n; i++)cout << a[i] << " ";cout << endl;
		// for(int i = 1; i <= n; i++)cout << b[i] << " ";cout << endl;
		while(i >= en[su].st and su <= n and yer[en[su].nd] == b[en[su].nd])
			su++;
		if(su <= n and i >= en[su].st){
			int xx = en[su].nd;
			// cout << xx << " icin " << yer[xx] << " " << b[xx] << endl;
			p[i] = yer[xx];
			q[i] = b[xx];
			swap(a[p[i]], a[q[i]]);
			swap(yer[a[p[i]]], yer[a[q[i]]]);
			su++;
		} else
			p[i] = q[i] = 1;
	}
	// cout << son << " -> ";for(int i = 1; i <= n; i++)cout << a[i] << " ";cout << endl;
	for(int i = 1; i <= n; i++)
		if(a[i] != i)
			return 0;
	return 1;
}

int findSwapPairs(int nn, int S[], int M, int X[], int Y[], int P[], int Q[]) {n = nn;m = M;
	for(int i = 1; i <= n; i++){
		s[i] = a[i] = S[i - 1] + EKLE;
		if(a[i] != i)
			f = 1;
	}
	if(!f)return 0;
	for(int i = 1; i <= m; i++){
		x[i] = X[i - 1] + EKLE;
		y[i] = Y[i - 1] + EKLE;
	}
	// int bas = 1, son = m;
	// while(bas < son){
	// 	if(dene(orta))
	// 		son = orta;
	// 	else
	// 		bas = orta + 1;
	// }
	// cout << orta << endl;
	for(int j = 1; j <= m; j++){
		if(!dene(j))continue;
		for(int i = 1; i <= j; i++){
			P[i - 1] = p[i] - EKLE;
			Q[i - 1] = q[i] - EKLE;
		}
		return j;	
	}
	return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 12 / 12
• Subtask 3: 16 / 16
• Subtask 4: 0 / 18
• Subtask 5: 0 / 20
• Subtask 6: 0 / 26