Submission #1280290

#	Time	Username	Problem	Language	Result	Execution time	Memory
1280290		PlayVoltz	Distributing Candies (IOI21_candies)	C++20	0 / 100	1116 ms	37980 KiB

candies

#include "candies.h"
#include <bits/stdc++.h>
using namespace std;

#define pii pair<int, int>
#define mp make_pair
#define pb push_back
#define fi first
#define se second

struct node{
	int s, e, m, mx, mn, val;
	node *l, *r;
	
	node(int S, int E){
		s=S, e=E, m=(s+e)/2;
		mx=mn=val=0;
		if (s!=e){
			l = new node(s, m);
			r = new node(m+1, e);
		}
	}
	void up(int i, int v){
		if (s==e){
			val=mn=mx=v;
			return;
		}
		if (i<=m)l->up(i, v);
		else r->up(i, v);
		val=l->val+r->val;
		mn=min(l->mn+r->val, r->mn);
		mx=max(l->mx+r->val, r->mx);
	}
	pii querymx(int left, int right){
		if (s==left && e==right)return mp(mx, val);
		if (right<=m)return l->querymx(left, right);
		else if (left>m)return r->querymx(left, right);
		pii ll=l->querymx(left, m), rr=r->querymx(m+1, right);
		return mp(max(ll.fi+rr.se, rr.fi), ll.se+rr.se);
	}
	pii querymn(int left, int right){
		if (s==left && e==right)return mp(mn, val);
		if (right<=m)return l->querymn(left, right);
		else if (left>m)return r->querymn(left, right);
		pii ll=l->querymn(left, m), rr=r->querymn(m+1, right);
		return mp(min(ll.fi+rr.se, rr.fi), ll.se+rr.se);
	}
}*st;

vector<int> distribute_candies(vector<int> c, vector<int> l, vector<int> r, vector<int> v){
	int n=c.size();
	vector<vector<pii> > updates(n+1);
	for (int i=0; i<l.size(); ++i)updates[l[i]].pb(mp(i, -v[i])), updates[r[i]+1].pb(mp(i, 0));
	st = new node(0, n);
	vector<int> ans(n);
	for (int i=0; i<n; ++i){
		for (auto c:updates[i])st->up(c.fi, c.se);
		int low=-1, high=n;
		while (low+1<high){
			int mid=(low+high)/2;
			if (st->querymx(mid, n-1).fi-st->querymn(mid, n-1).fi>c[i])low=mid;
			else high=mid;
		}
		if (low==-1)ans[i]=-st->querymn(0, n-1).fi;
		else{
			int mx=st->querymx(low, n-1).fi, mn=st->querymn(low, n-1).fi;
			if (v[low]>0)ans[i]=c[i]-mx;
			else ans[i]=-mn;
		}
	}
	return ans;
}

• Subtask 1: 0 / 3
• Subtask 2: 0 / 8
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29
• Subtask 5: 0 / 33