#include <bits/stdc++.h>
using namespace std;
template<class T, class U>
void ckmin(T &a, U b)
{
if (a > b) a = b;
}
template<class T, class U>
void ckmax(T &a, U b)
{
if (a < b) a = b;
}
#define MP make_pair
#define PB push_back
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define FOR(i, a, b) for (auto i = (a); i < (b); i++)
#define FORD(i, a, b) for (auto i = (a) - 1; i >= (b); i--)
#define SZ(x) ((int) ((x).size()))
#define ALL(x) (x).begin(), (x).end()
#define LIM 100000007
#define INF 1000000007
#define LLINF 2696969696969696969ll
#define MAXN 300013
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<pii> vpi;
typedef vector<pll> vpl;
typedef pair<pii, pii> ppp;
int N, K, Q, P;
vector<ppp> arr;
vector<pii> events[MAXN];
pii quer[MAXN];
int ans[MAXN];
vi compress;
vi pos;
vpi func;
int mx, iter, freq;
int32_t main()
{
ios_base::sync_with_stdio(0); cin.tie(0);
cin >> N >> K >> Q;
arr.resize(N);
FOR(i, 0, N)
{
cin >> arr[i].fi.se >> arr[i].fi.fi >> arr[i].se.fi >> arr[i].se.se;
arr[i].fi.fi--;
}
FOR(i, 0, Q)
{
cin >> quer[i].fi >> quer[i].se; //location, time
compress.PB(quer[i].se);
}
compress.PB(0); compress.PB(INF);
sort(ALL(compress));
compress.erase(unique(ALL(compress)), compress.end());
FOR(i, 0, N)
{
arr[i].fi.fi = LB(ALL(compress), arr[i].fi.fi) - compress.begin();
arr[i].fi.se = UB(ALL(compress), arr[i].fi.se) - compress.begin() - 1;
}
FOR(i, 0, Q)
{
quer[i].se = LB(ALL(compress), quer[i].se) - compress.begin();
}
//type, location, times (whaever)
//ok this is type what:
sort(ALL(arr));
freq = 0;
FOR(i, 0, N)
{
//consider the distance functions formed! query max!
//so for each of the things you should have shit of the form: a distance function that starts at time t that has x-intercept t1
pos.PB(arr[i].fi.se);
if (i == N - 1 || arr[i].fi.fi != arr[i + 1].fi.fi)
{
//build the shit! how about let's try the negatives first
func.PB({0, pos[0]});
FOR(j, 1, SZ(pos))
{
func.PB({(pos[j - 1] + pos[j] + 1) / 2, pos[j]});
}
pos.clear();
freq++;
}
}
if (freq != K)
{
func.PB({0, INF});
}
sort(ALL(func));
mx = -INF; iter = 0;
FOR(i, 0, SZ(func))
{
while(iter < Q && quer[iter].fi < func[i].fi)
{
ckmax(ans[iter], -quer[iter].fi + mx);
iter++;
}
ckmax(mx, func[i].se);
}
freq = 0;
FOR(i, 0, N)
{
pos.PB(arr[i].fi.se);
if (i == N - 1 || arr[i].fi.fi != arr[i + 1].fi.fi)
{
//build the shit! how about let's try the negatives first
func.PB({LIM, -pos.back()});
FORD(j, SZ(func) - 1, 0)
{
func.PB({(pos[j] + pos[j + 1]) / 2, -pos[j]});
}
pos.clear();
freq++;
}
}
if (freq != K)
{
func.PB({LIM, INF});
}
sort(ALL(func));
mx = -INF; iter = Q - 1;
FORD(i, SZ(func), 0)
{
while(iter >= 0 && quer[iter].fi > func[i].fi)
{
ckmax(ans[iter], quer[iter].fi + mx);
iter--;
}
ckmax(mx, func[i].se);
}
//events: OPEN/CLOSE a store at time t, position p, type x, ASK at time t, position p
FOR(i, 0, Q)
{
cout << (ans[i] >= LIM ? -1 : ans[i]) << '\n';
}
return 0;
}
| # |
결과 |
실행 시간 |
메모리 |
Grader output |
| 1 |
Incorrect |
8 ms |
7416 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
결과 |
실행 시간 |
메모리 |
Grader output |
| 1 |
Incorrect |
8 ms |
7416 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
결과 |
실행 시간 |
메모리 |
Grader output |
| 1 |
Runtime error |
489 ms |
36604 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
결과 |
실행 시간 |
메모리 |
Grader output |
| 1 |
Runtime error |
479 ms |
46552 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
결과 |
실행 시간 |
메모리 |
Grader output |
| 1 |
Incorrect |
8 ms |
7416 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
결과 |
실행 시간 |
메모리 |
Grader output |
| 1 |
Incorrect |
8 ms |
7416 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
