Submission #1244851

#	Time	Username	Problem	Language	Result	Execution time	Memory
1244851		AlperenT_	Sphinx's Riddle (IOI24_sphinx)	C++20	50 / 100	149 ms	1380 KiB

sphinx

#include "sphinx.h"
#include <bits/stdc++.h> 
#pragma GCC optimize("O3,unroll-loops") 
#pragma GCC target("avx2") 
#define pb push_back
#define F first
#define pii pair<int,int> 
#define all(a) a.begin(),a.end()
#define S second 
#define sz(a) (int)a.size()
#define rep(i , a , b) for(int i = (a) ; i <= (b) ; i++)
#define per(i , a , b) for(int i = (a) ; i >= (b) ; i--)
#define ld double
#define ll long long 
using namespace std ;
const int maxn = 500 + 100 , inf = 1e9 , mod = 998244353;
vector <int> vec[maxn] , G[maxn] ;
int par[maxn] , mark[maxn] , n;
vector <int> y;
void dfs(int v){
  mark[v] =1 ;
  for(int u : G[v]){
    if(y[u] == n && mark[u] == 0)dfs(u);
  }
}
int smq = 0 ; 
int que(vector <int> x){
  int sm =perform_experiment(x);
  smq--;
  if(smq < 0)while(1){}
  y =x; 
  rep(i ,0 , n-1){
    mark[i] =0 ; 
  }
  rep(i ,0, n-1){
    if(mark[i] ==0 && x[i] == n){
      dfs(i) ;
      sm-- ;
    }
  }
  return sm ; 
}
std::vector<int> find_colours(int N, std::vector<int> X, std::vector<int> Y) {
  n = N; 
  smq = (n-1) * 8 + n ;
  rep(i , 0 ,sz(X)-1){
    G[X[i]].pb(Y[i]);
    G[Y[i]].pb(X[i]); 
  }
  rep(i , 0 ,n-1)vec[i].pb(i);
  vector<int> az ;
  rep(i , 0 , n-1){
    while(1){
      vector <int> e ;
      rep(j , 0 ,n-1){
        if(j > i){
          e.pb(n);
          continue ;
        }
        e.pb(-1);
      }
      if(que(e) == 1 + sz(az)){
        az.pb(i) ;
        break ;
      }
      int l =-1 , r = sz(az)-1;
      while(r-l > 1){
        int m = (l+r)/2 ;
        vector <int> e ;
        rep(i , 0 ,n-1)e.pb(n) ;
        e[i] = -1 ;
        rep(i , 0 ,m){
          int x = az[i] ;
          for(int y : vec[x]){
            e[y] = -1 ;
          }
        }
        if(que(e) == 1 + (m+1)){
          l = m; 
        }else{
          r = m ;
        }
      }
      par[az[r]] = i;
      for(int x : vec[az[r]])vec[i].pb(x) ;
      vector <int> az2 ;
      rep(i , 0 ,sz(az)-1){
        if(i == r)continue;
        az2.pb(az[i]);
      }
      az = az2 ;
    }
  }
  int cnt = 0;
  vector <int> ans ;
  rep(i , 0 ,n-1)ans.pb(0);
  for(int x : az){
    for(int y : vec[x]){
      ans[y] = cnt ;
    }
    cnt++ ;
  }
  return ans ;
}

• Subtask 0: 0 / 0
• Subtask 1: 1.5 / 3
• Subtask 2: 3.5 / 7
• Subtask 3: 16.5 / 33
• Subtask 4: 10.5 / 21
• Subtask 5: 18 / 36