# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
1242386 | muhammad-mutahir | 캥거루 (CEOI16_kangaroo) | C++20 | 52 ms | 55112 KiB |
#ifdef AVX2
#pragma GCC target ("avx2")
#pragma GCC optimize ("O3")
#pragma GCC optimize ("unroll-loops")
#endif
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define print(l) for(auto i:l)cout<<i<<" ";cout<<endl;
#define se second
#define fi first
#define input(t,l,n) vector<t>l(n);for(int i = 0;i<n;i++)cin>>l[i];
#define pb push_back
#define all(l) l.begin(),l.end()
#define endl '\n'
const int M = 1e9+7;
const int inf = 1e18;
void io(){
#ifndef ONLINE_JUDGE
freopen("inp.in","r",stdin);
freopen("out.in","w",stdout);
#endif
}
void fastio(){
ios::sync_with_stdio(0);//DO NOT USE IN INTERACTIVE
cin.tie(0), cout.tie(0);
cout << fixed<<setprecision(9);
srand(time(0));
}
vector<vector<vector<int>>>adj;
vector<int>vis,ch,dis;
int n,m,q;
const int N =1e5+10;
const int lg = 20;
int sp[N][lg];
int sp1[N][lg];
void buildsp(){
for(int i = 1;i<lg;i++){
for(int j = 1;j<=m;j++){
sp[j][i] = sp[sp[j][i-1]][i-1];
sp1[j][i] = max(sp1[j][i-1],sp1[sp[j][i-1]][i-1]);
}
}
}
int kp(int c,int p){
for(int i = lg-1;i>=0;i--){
if((p&(1<<i))){
c = sp[c][i];
}
}
return c;
}
void dfs(int c){
for(auto f:adj[c]){
int i = f[0];
if(!vis[i]){
dis[i] = dis[c]+1;
sp[i][0] = c;
sp1[i][0] = f[1];
vis[i] = 1;
dfs(i);
}
}
}
int lca(int u,int v){
if(dis[u] > dis[v] ){
swap(u,v);
}
v = kp(v,dis[v]-dis[u]);
if(v == u){
return u;
}
// cout<<u<<" "<<v<<"<<<<<<<<<<"<<endl;
for(int i = lg-1;i>=0;i--){
if(sp[u][i]!= sp[v][i]){
u = sp[u][i];
v = sp[v][i];
}
}
return sp[u][0];
}
int dp[2000+10][2000+10][3];
void solve(){
int f,s;
cin>>n>>s>>f;
if(s == 1 or f == 1){
dp[1][1][1] = 1;
}
else{
dp[1][1][0] = 1;
}
// dp[1][1] = 1;
for(int i = 1;i<n;i++){
for(int j = 1;j<=i;j++){
if(i+1 == s or i+1 == f){
for(int k = 0;k<2;k++){
dp[i+1][j+1][k+1] += dp[i][j][k];
dp[i+1][j][k+1] += dp[i][j][k];
dp[i+1][j+1][k+1] %=M;
dp[i+1][j][k+1] %=M;
}
}
else{
for(int k = 0;k<3;k++){
dp[i+1][j+1][k] += (dp[i][j][k]*(j+1-k))%M;
dp[i+1][j-1][k] += (dp[i][j][k]*(j-1))%M;
dp[i+1][j+1][k] %=M;
dp[i+1][j-1][k] %=M;
}
}
}
}
cout<<dp[n][1][2]<<endl;
}
signed main(){
// io();
fastio();
int t = 1;
// cin>>t;
while(t--)solve();
}
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