Submission #123995

#	Time	Username	Problem	Language	Result	Execution time	Memory
123995		onjo0127	Naan (JOI19_naan)	C++11	29 / 100	131 ms	14460 KiB

naan

#include <bits/stdc++.h>
using namespace std;
using ll = __int128;
using pll = pair<ll, ll>;
#define X first
#define Y second
 
const pll INF = {1LL*1e18, 1};
int N, L, V[2009][2009], A[2009];
pll D[2009][2009];
 
bool operator <(pll P, pll Q) {
	return (__int128)P.X * Q.Y < (__int128)Q.X * P.Y;
}

pll f(ll a, ll b) {
	ll gcd = __gcd(a, b);
	return {a / gcd, b / gcd};
}
 
void R(int i) {
	ll a, b, sa = 0, sb = 1;
	tie(sa, sb) = f(sa, sb);
	for(int j=0, k=1; j<L; j++) {
		// sa / sb + V[i][j] >= A[i] / N * k
		if((__int128)sa * N + (__int128)V[i][j] * sb * N >= (__int128)A[i] * sb * k) {
			// (a / b) * V[i][j] + (sa / sb) == A[i] / N * k
			// a/b * V[i][j] * sb * N + sa * N == A[i] * sb * k
			// a/b * V[i][j] * sb * N == A[i] * sb * k - sa * N;
			b = (__int128)V[i][j] * sb * N;
			a = (__int128)b * j + (__int128)A[i] * sb * k - (__int128)sa * N;
			D[i][k] = f(a, b);
			++k;
		}
		sa += (__int128)sb * V[i][j];
		tie(sa, sb) = f(sa, sb);
	}
}

bool chk[2009];

int main() {
	scanf("%d%d",&N,&L);
	for(int i=1; i<=N; i++) {
		for(int j=0; j<L; j++) {
			scanf("%d",&V[i][j]);
			A[i] += V[i][j];
		}
		R(i);
	}
	vector<pll> pos; vector<int> P;
	for(int i=1; i<=N; i++) {
		pll mn = INF; int mni = -1;
		for(int j=1; j<=N; j++) if(!chk[j]) {
			if(D[j][i] < mn) {
				mn = D[j][i];
				mni = j;
			}
		}
		pos.push_back(mn);
		P.push_back(mni);
		chk[mni] = 1;
	}
	for(int i=0; i<N-1; i++) printf("%lld %lld\n", (long long)pos[i].X, (long long)pos[i].Y);
	for(auto& it: P) printf("%d ", it);
	return 0;
}

Compilation message (stderr)

naan.cpp: In function 'int main()':
naan.cpp:43:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d",&N,&L);
  ~~~~~^~~~~~~~~~~~~~
naan.cpp:46:9: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
    scanf("%d",&V[i][j]);
    ~~~~~^~~~~~~~~~~~~~~

• Subtask 1: 5 / 5
• Subtask 2: 24 / 24
• Subtask 3: 0 / 71