#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e9+7;
const ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<ll,ii>
#define id pair<ll,vector<ll> >
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Training
#include "biscuits.h"
ll sum[65] = {0};
ll dp[65][65];
ll solve(ll i,ll j){
if(i == -1){
return 1;
}
if(dp[i][j] != -1){
return dp[i][j];
}
ll ans;
if(sum[j] & (1LL<<i)){
ans = solve(i-1,62);
if(sum[i] >= (1LL<<i)){
if((sum[j] % (1LL<<(i+1))) < sum[i]){
ans += solve(i-1,j);
}
else{
ans += solve(i-1,i);
}
}
}
else{
ans = solve(i-1,j);
}
return dp[i][j] = ans;
}
long long count_tastiness(long long x, std::vector<long long> a){
while(a.size() < 62){
a.pb(0);
}
sum[0] = 0;
memset(dp,-1,sizeof dp);
f(i,0,61){
sum[i] = a[i] * (1LL<<i);
if(i){
sum[i] += sum[i-1];
}
}
f(i,0,61){
sum[i] /= x;
sum[i] = min(sum[i],(1LL<<(i+1)) - 1);
}
sum[62] = (1LL<<60) - 1;
ll ans = 1;
f(j,0,61){
if(sum[j] >= (1LL<<j)){
ans += solve(j-1,j);
}
}
return ans;
}
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