제출 #120531

#제출 시각아이디문제언어결과실행 시간메모리
120531gs14004다리 (APIO19_bridges)C++17
100 / 100
2061 ms9128 KiB
#include <bits/stdc++.h> using namespace std; const int MAXN = 100005; const int B = 800; using lint = long long; using pi = pair<int, int>; int n, m, q; bool in_must[MAXN]; bool in_quer[MAXN]; struct disj{ int pa[MAXN]; int sz[MAXN]; void init(int n){ iota(pa, pa + n + 1, 0); fill(sz, sz + n + 1, 1); } int find(int x){ return pa[x] == x ? x : find(pa[x]); } bool uni(int p, int q){ p = find(p); q = find(q); if(p == q) return 0; if(sz[p] < sz[q]) swap(p, q); pa[q] = p; sz[p] += sz[q]; return 1; } bool uni(int p, int q, vector<pi> &rvt){ p = find(p); q = find(q); if(p == q) return 0; if(sz[p] < sz[q]) swap(p, q); rvt.emplace_back(q, -1); pa[q] = p; rvt.emplace_back(p, sz[p]); sz[p] += sz[q]; return 1; } void revert(vector<pi> &v){ reverse(v.begin(), v.end()); for(auto &i : v){ if(i.second == -1) pa[i.first] = i.first; else sz[i.first] = i.second; } v.clear(); } int getSz(int x){ return sz[find(x)]; } }disj; struct edg{ int s, e, x, idx; bool operator<(const edg &e)const{ return x < e.x; } }e[MAXN]; struct qry{ int pos, idx, thres; bool operator<(const qry &q)const{ return thres < q.thres; } }; int t[MAXN], x[MAXN], y[MAXN]; int rev[MAXN], ret[MAXN]; int aux[MAXN]; int main(){ scanf("%d %d",&n,&m); for(int i=0; i<m; i++){ scanf("%d %d %d",&e[i].s,&e[i].e,&e[i].x); e[i].x = 1696969696 - e[i].x; e[i].idx = i + 1; } scanf("%d",&q); for(int i=0; i<q; i++){ scanf("%d %d %d",&t[i],&x[i],&y[i]); y[i] = 1696969696 - y[i]; } sort(e, e + m); for(int i=0; i<q; i+=B){ for(int i=0; i<m; i++) rev[e[i].idx] = i; memset(in_must, 0, sizeof(in_must)); vector<int> must; vector<int> maybe; disj.init(n); for(int j=i; j<i+B && j<q; j++){ if(t[j] == 1){ int pos = rev[x[j]]; in_quer[pos] = 1; } } for(int i=0; i<m; i++){ if(in_quer[i]) continue; if(disj.uni(e[i].s, e[i].e)){ must.push_back(i); } } vector<qry> qr; vector<int> drog; for(int j=i; j<i+B && j<q; j++){ if(t[j] == 2){ qr.push_back({x[j], j, y[j]}); } if(t[j] == 1){ if(in_quer[rev[x[j]]]){ in_quer[rev[x[j]]] = 0; drog.push_back(x[j]); } } } sort(qr.begin(), qr.end()); disj.init(n); int ptr = 0; for(auto &k : qr){ while(ptr < must.size() && e[must[ptr]].x <= k.thres){ disj.uni(e[must[ptr]].s, e[must[ptr]].e); ptr++; } vector<pi> logs; for(int j=i; j<k.idx; j++){ if(t[j] == 1){ aux[x[j]] = y[j]; } } for(auto &i : maybe){ if(e[i].x <= k.thres){ disj.uni(e[i].s, e[i].e, logs); } } for(auto &i : drog){ int pos = rev[i]; int cost = aux[i]; if(cost == 0) cost = e[pos].x; if(cost <= k.thres){ disj.uni(e[pos].s, e[pos].e, logs); } } ret[k.idx] = disj.getSz(k.pos); disj.revert(logs); for(int j=i; j<k.idx; j++){ if(t[j] == 1){ aux[x[j]] = 0; } } } for(int j=i; j<q && j<i+B; j++){ if(t[j] == 1) aux[x[j]] = y[j]; } vector<edg> l, r; for(int i=0; i<m; i++){ if(aux[e[i].idx]){ e[i].x = aux[e[i].idx]; aux[e[i].idx] = 0; r.push_back(e[i]); } else l.push_back(e[i]); } sort(r.begin(), r.end()); merge(l.begin(), l.end(), r.begin(), r.end(), e); } for(int i=0; i<q; i++) if(t[i] == 2) printf("%d\n", ret[i]); }

컴파일 시 표준 에러 (stderr) 메시지

bridges.cpp: In function 'int main()':
bridges.cpp:119:14: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
    while(ptr < must.size() && e[must[ptr]].x <= k.thres){
          ~~~~^~~~~~~~~~~~~
bridges.cpp:72:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d",&n,&m);
  ~~~~~^~~~~~~~~~~~~~~
bridges.cpp:74:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d %d %d",&e[i].s,&e[i].e,&e[i].x);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
bridges.cpp:78:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d",&q);
  ~~~~~^~~~~~~~~
bridges.cpp:80:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d %d %d",&t[i],&x[i],&y[i]);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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