답안 #120322

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
120322 2019-06-24T07:59:58 Z tmwilliamlin168 Printed Circuit Board (CEOI12_circuit) C++14
85 / 100
51 ms 8816 KB
#include <bits/stdc++.h>
using namespace std;

#define ll long long

const int mxN=2e5;
int n, l, r;
ll x[mxN], y[mxN];
vector<int> v, s;
bool b[mxN];

ll cp(int a, int b, int c) {
	return (y[c]-y[a])*(x[b]-x[a])-(y[b]-y[a])*(x[c]-x[a]);
}

int main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	cin >> n;
	for(int i=0; i<n; ++i) {
		cin >> x[i] >> y[i];
		if(!i||cp(n, l, i)>0||!cp(n, l, i)&&x[i]<x[l])
			l=i;
		if(!i||cp(n, r, i)<0||!cp(n, r, i)&&x[i]<x[r])
			r=i;
	}
	//cout << l << " " << r << endl;
	int ic=cp((l+n-1)%n, l, (l+1)%n)>0?1:n-1;
	for(; l^r; l=(l+ic)%n)
		v.push_back(l);
	v.push_back(r);
	//cout << "a" << endl;
	//for(int i : v)
		//cout << x[i] << " " << y[i] << endl;
	s={0, 1};
	for(int i=2; i<v.size(); ++i) {
		//cout << i << endl;
		//for(int si : s)
			//cout << si << " ";
		//cout << endl;
		//side going strictly forwards
		if(cp(n, v[i-1], v[i])<0) {
			//last side went strictly backwards and current side is now hidden
			if(cp(n, v[i-2], v[i-1])>0&&cp(v[i-2], v[i-1], v[i])<0) {
				//while hidden
				while(cp(n, v[s.back()], v[i])<=0)
					++i;
				s.pop_back();
				//while one of s.back() and i hides the other and it is actually s.back() which is hidden 
				while(cp(n, v[s.back()], v[i])>=0&&cp(v[i-1], v[i], v[s.back()])<0)
					s.pop_back();
				//i is hidden
				if(cp(n, v[s.back()], v[i])>=0) {
					int j=i, c=0;
					//while i is not to the right of s.back() or i is hidden by segment j
					while(cp(n, v[s.back()], v[i])>=0||!c) {
						//if this is the first side, c will be one iff the new edge goes forwards and is not hidden by segment j
						if(i==j)
							c=cp(n, v[i], v[i+1])<0&&cp(v[i-1], v[i], v[i+1])>0;
						//if we start not to the right of j but end up to the right of j and j does not hide i+1
						if(cp(n, v[j], v[i])>=0&&cp(n, v[j], v[i+1])<0&&cp(v[i], v[i+1], v[j])>0)
							++c;
						//if we start to the right of j but end up not to the right of j and j does not hide i+1
						if(cp(n, v[j], v[i])<0&&cp(n, v[j], v[i+1])>=0&&cp(v[i], v[i+1], v[j])<0)
							--c;
						++i;
						while(i>=v.size());
					}
				}
			}
		}
		//side going strictly backwards
		else if(cp(n, v[i-1], v[i])>0) {
			//last side went strictly forwards and current side is now hidden
			if(cp(n, v[i-2], v[i-1])<0&&cp(v[i-2], v[i-1], v[i])>0) {
				//while hidden
				while(cp(n, v[s.back()], v[i])>=0)
					++i;
			} else {
				//while one of s.back() and i hides the other and it is actually s.back() which is hidden
				//note <= here so we can pop off v[i-1]
				while(cp(n, v[s.back()], v[i])>=0&&cp(v[i-1], v[i], v[s.back()])<=0)
					s.pop_back();
				//i is hidden
				if(cp(n, v[s.back()], v[i])>=0) {
					int j=i, c=0;
					//while i is not to the right of s.back() or i is hidden by segment j
					while(cp(n, v[s.back()], v[i])>=0||!c) {
						//if this is the first side, c will be one iff the new edge goes forwards and is not hidden by segment j
						if(i==j)
							c=cp(n, v[i], v[i+1])<0&&cp(v[i-1], v[i], v[i+1])>0;
						//if we start not to the right of j but end up to the right of j and j does not hide i+1
						if(cp(n, v[j], v[i])>=0&&cp(n, v[j], v[i+1])<0&&cp(v[i], v[i+1], v[j])>0)
							++c;
						//if we start to the right of j but end up not to the right of j and j does not hide i+1
						if(cp(n, v[j], v[i])<0&&cp(n, v[j], v[i+1])>=0&&cp(v[i], v[i+1], v[j])<0)
							--c;
						++i;
						while(i>=v.size());
					}
				}
			}
		}
		//side not changing angle
		else {
			//if new point hides old point
			if((cp(n, v[i-2], v[i-1])<0)==(cp(v[i-2], v[i-1], v[i])<0))
				s.pop_back();
			//last side went strictly forwards and current side is now hidden
			else if(cp(n, v[i-2], v[i-1])<0) {
				//while hidden
				while(cp(n, v[s.back()], v[i])>=0)
					++i;
			}
			//last side went strictly backwards and current side is now hidden
			else {
				//while hidden
				while(cp(n, v[s.back()], v[i])<=0)
					++i;
				s.pop_back();
				//while one of s.back() and i hides the other and it is actually s.back() which is hidden 
				while(cp(n, v[s.back()], v[i])>=0&&cp(v[i-1], v[i], v[s.back()])<0)
					s.pop_back();
				//i is hidden
				if(cp(n, v[s.back()], v[i])>=0) {
					int j=i, c=0;
					//while i is not to the right of s.back() or i is hidden by segment j
					while(cp(n, v[s.back()], v[i])>=0||!c) {
						//if this is the first side, c will be one iff the new edge goes forwards and is not hidden by segment j
						if(i==j)
							c=cp(n, v[i], v[i+1])<0&&cp(v[i-1], v[i], v[i+1])>0;
						//if we start not to the right of j but end up to the right of j and j does not hide i+1
						if(cp(n, v[j], v[i])>=0&&cp(n, v[j], v[i+1])<0&&cp(v[i], v[i+1], v[j])>0)
							++c;
						//if we start to the right of j but end up not to the right of j and j does not hide i+1
						if(cp(n, v[j], v[i])<0&&cp(n, v[j], v[i+1])>=0&&cp(v[i], v[i+1], v[j])<0)
							--c;
						++i;
						while(i>=v.size());
					}
				}
			}
		}
		s.push_back(i);
	}
	cout << s.size() << "\n";
	for(int a : s)
		b[v[a]]=1;
	for(int i=0; i<n; ++i)
		if(b[i])
			cout << i+1 << " ";
}

Compilation message

circuit.cpp: In function 'int main()':
circuit.cpp:23:37: warning: suggest parentheses around '&&' within '||' [-Wparentheses]
   if(!i||cp(n, l, i)>0||!cp(n, l, i)&&x[i]<x[l])
                         ~~~~~~~~~~~~^~~~~~~~~~~
circuit.cpp:25:37: warning: suggest parentheses around '&&' within '||' [-Wparentheses]
   if(!i||cp(n, r, i)<0||!cp(n, r, i)&&x[i]<x[r])
                         ~~~~~~~~~~~~^~~~~~~~~~~
circuit.cpp:37:16: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  for(int i=2; i<v.size(); ++i) {
               ~^~~~~~~~~
circuit.cpp:68:14: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
       while(i>=v.size());
             ~^~~~~~~~~~
circuit.cpp:100:14: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
       while(i>=v.size());
             ~^~~~~~~~~~
circuit.cpp:140:14: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
       while(i>=v.size());
             ~^~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 384 KB Output is correct
2 Correct 2 ms 384 KB Output is correct
3 Correct 3 ms 512 KB Output is correct
4 Correct 3 ms 428 KB Output is correct
5 Correct 4 ms 640 KB Output is correct
6 Correct 5 ms 640 KB Output is correct
7 Correct 6 ms 1024 KB Output is correct
8 Correct 4 ms 640 KB Output is correct
9 Correct 4 ms 640 KB Output is correct
10 Correct 5 ms 640 KB Output is correct
11 Correct 5 ms 768 KB Output is correct
12 Correct 6 ms 1024 KB Output is correct
13 Correct 9 ms 1280 KB Output is correct
14 Correct 10 ms 1400 KB Output is correct
15 Correct 12 ms 1792 KB Output is correct
16 Correct 21 ms 2896 KB Output is correct
17 Correct 23 ms 2552 KB Output is correct
18 Incorrect 37 ms 3748 KB Output isn't correct
19 Runtime error 45 ms 8816 KB Execution killed with signal 11 (could be triggered by violating memory limits)
20 Runtime error 51 ms 8816 KB Execution killed with signal 11 (could be triggered by violating memory limits)