Submission #119379

#	Time	Username	Problem	Language	Result	Execution time	Memory
119379		ryansee	Strah (COCI18_strah)	C++14	22 / 110	1080 ms	19920 KiB

strah

#include "bits/stdc++.h"
using namespace std;
#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define LLINF 1e18//1234567890987654321
#define INF 1234567890
#define pb push_back
#define ins insert
#define f first
#define s second
#define db 0
#define EPS (1e-7)    //0.0000001 the value
#define PI (acos(-1))
#define MAXN 100006
#define MAXK 26
#define MAXX 15000006
#define ll int
#define rep0(kk, l1, l2)for(ll kk = l1; kk < l2; kk++)
#define rep1(kk, l1, l2)for(ll kk = l1; kk <= l2; kk++)
#define forit(it, A) for(set<ll>::iterator it = A.begin(); it != A.end(); it++)
#define mmst(x, v) memset((x), v, sizeof ((x)));
#define bg(ms) (*ms.begin())
#define ed(ms) (*prev(ms.end(), 1))
#define addedge(a, b, c, v) v[(a)].pb(pi((b), (c))); v[(b)].pb(pi((a), (c)))
#define ph push
#define btinpct(x) __builtin_popcountll(x)
#define p2(x) (1LL<<(x))
#define all(x) (x).begin(), (x).end()
#define lbd(x, y) lower_bound(all(x), y)
#define ubd(x, y) upper_bound(all(x), y)
typedef pair <ll, ll> pi;
typedef pair <ll, pi> spi;
typedef pair <pi, pi> dpi;
ll n, m, sum[2006][2006];
long long ans;
char grid[2006][2006];
ll sumup(ll a, ll b, ll c, ll d)
{
	return sum[c][d] - sum[c][b-1] - sum[a-1][d] + sum[a-1][b-1];
}
int main()
{
	FAST
	cin >> n >> m;
	for(ll i = 1; i <= n; i++)
	{
		for(ll j = 1; j <= m; j++)
		{
			cin >> grid[i][j];
			sum[i][j] = sum[i-1][j] + sum[i][j-1] - sum[i-1][j-1] + (grid[i][j] == '#');
		}
	}
	for(ll i = 1; i <= n; i++)
	{
		for(ll j = 1; j <= m; j++)
		{
			if(grid[i][j] == '#')continue;
			for(ll nx = i; nx <= n; nx++)
			{
				for(ll ny = j; ny <= m; ny++)
				{
					if(grid[nx][ny] == '#')continue;
					if(sumup(i, j, nx, ny) == 0)
					{
						ans += (abs(i-nx)+1)*(abs(j-ny)+1);
						// if(nx == i && ny == j)ans -= 1;
					}
				}
			}
		}
	}
	cout << ans << "\n";
}

• Subtask 1: 11 / 11
• Subtask 2: 11 / 11
• Subtask 3: 0 / 11
• Subtask 4: 0 / 11
• Subtask 5: 0 / 11
• Subtask 6: 0 / 11
• Subtask 7: 0 / 11
• Subtask 8: 0 / 11
• Subtask 9: 0 / 11
• Subtask 10: 0 / 11