제출 #1183626

#제출 시각아이디문제언어결과실행 시간메모리
1183626TymondGap (APIO16_gap)C++20
0 / 100
40 ms3260 KiB
#include <bits/stdc++.h> #include "gap.h" using namespace std; using ll = long long; using ld = long double; #define fi first #define se second #define vi vector<int> #define vll vector<long long> #define pii pair<int, int> #define pll pair<long long, long long> #define pb push_back #define mp make_pair #define eb emplace_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); mt19937_64 rng64(chrono::high_resolution_clock::now().time_since_epoch().count()); inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);} inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);} #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif struct custom_hash { static uint64_t splitmix64(uint64_t x) { x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; struct pair_hash{ size_t operator()(const pair<int,int>&x)const{ return hash<long long>()(((long long)x.first)^(((long long)x.second)<<32)); } }; const ll INF = 1e18; ll brut(int n){ vll a(n); ll l = 0LL; ll p = INF; for(int i = 0; i < n / 2; i++){ ll x, y; MinMax(l, p, &x, &y); a[i] = x; a[n - i - 1] = y; l = x + 1; p = y - 1; } ll ans = 0LL; for(int i = 0; i + 1 < n; i++){ ans = max(ans, a[i + 1] - a[i]); } return ans; } ll findGap(int T, int n){ if(T == 1){ return brut(n); } ll mn, mx; MinMax(0LL, INF, &mn, &mx); ll R = mx - mn; if(mx == mn){ return 0LL; } vector<pll> vec; ll x = mn; ll ans = 0LL; for(int i = 0; i < n - 1; i++){ ll len = R / (n - 1); //if(R % (n - 1) > i){ // len++; //} ll currMn, currMx; MinMax(x, x + len, &currMn, &currMx); if(currMn != (ll)-1){ vec.pb(mp(currMn, currMx)); } x += (len + 1); } for(int i = 0; i + 1 < sz(vec); i++){ ans = max(ans, vec[i + 1].fi - vec[i].se); } return ans; }
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