Submission #1164309

#TimeUsernameProblemLanguageResultExecution timeMemory
1164309Zero_OPWorst Reporter 3 (JOI18_worst_reporter3)C++20
12 / 100
350 ms327680 KiB
#include <bits/stdc++.h>

using namespace std;

#define FOR(i, l, r) for(int i = (l); i < (r); ++i)
#define ROF(i, r, l) for(int i = (r) - 1; i >= (l); --i)

#define mp make_pair
#define mt make_tuple
#define ff first
#define ss second

#define all(v) begin(v), end(v)
#define rall(v) rbegin(v), rend(v)
#define pb push_back
#define eb emplace_back
#define sz(v) (int)v.size()
#define sum_of(v) accumulate(all(v), 0ll)

#define dbg(x) "[" #x " = " << (x) << "]"

template<typename T>
      bool minimize(T& a, const T& b){
            if(a > b) return a = b, true;
            return false;
      }

template<typename T>
      bool maximize(T& a, const T& b){
            if(a < b) return a = b, true;
            return false;
      }

using ll = long long;
using db = double;
using ld = long double;
using ull = unsigned long long;

using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;

using vi = vector<int>;
using vb = vector<bool>;
using vc = vector<char>;
using vl = vector<ll>;
using vd = vector<db>;

using vpi = vector<pi>;
using vpl = vector<pl>;

void setIO(){
      ios_base::sync_with_stdio(0); cin.tie(0);
#ifdef LOCAL
      freopen("task.inp", "r", stdin);
      freopen("task.out", "w", stdout);
#endif // LOCAL
}

int main(){
      setIO();

      int N, Q;
      cin >> N >> Q;

      vi d(N+1);
      FOR(i, 1, N+1) cin >> d[i];

      const int MAXT = 1e3 + 1;

      vector<vi> blocks(MAXT);

      vi cur(N+1);
      FOR(i, 0, N+1) cur[i] = -i;

      blocks[0] = cur;

      FOR(t, 1, MAXT){
            ++cur[0];
            FOR(i, 1, N+1){
                  if(cur[i-1] - cur[i] > d[i]){
                        cur[i] = cur[i-1] - 1;
                  }
            }

            blocks[t] = cur;

//            FOR(i, 0, N+1) cout << cur[i] << ' '; cout << '\n';
      }

      while(Q--){
            int T, L, R;
            cin >> T >> L >> R;

            int l = lower_bound(rall(blocks[T]), L) - blocks[T].rbegin();
            int r = upper_bound(rall(blocks[T]), R) - blocks[T].rbegin();
            cout << r - l << '\n';
      }

      return 0;
}
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