제출 #1147845

#제출 시각아이디문제언어결과실행 시간메모리
1147845Theo830Palembang Bridges (APIO15_bridge)C++20
0 / 100
1 ms1096 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; const ll INF = 1e9+7; const ll MOD = 998244353; typedef pair<ll,ll> ii; #define iii pair<ii,ll> #define f(i,a,b) for(ll i = a;i < b;i++) #define pb push_back #define vll vector<ll> #define F first #define S second #define all(x) (x).begin(), (x).end() ///I hope I will get uprating and don't make mistakes ///I will never stop programming ///sqrt(-1) Love C++ ///Please don't hack me ///@TheofanisOrfanou Theo830 ///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst) ///Stay Calm ///Look for special cases ///Beware of overflow and array bounds ///Think the problem backwards ///Training ll anss = 1e18; char p[100005],q[100005]; ll x[100005],y[100005]; ll n; ll dp[100005]; vector<ll>vale; ll solve(ll a,ll b){ ll ans = 0; f(i,0,n){ if(p[i] != q[i]) ans += min(abs(a - x[i]) + abs(a - y[i]),abs(b - x[i]) + abs(b - y[i])); } anss = min(ans,anss); return ans; } ll evre(ll z){ if(dp[z] != -1){ return dp[z]; } ll x = vale[z]; ll l = 0,r = vale.size()-2; ll C = 1e18; while(l <= r){ ll mid = (l+r)/2; ll A = solve(x,vale[mid]); ll B = solve(x,vale[mid+1]); C = min(C,A); C = min(C,B); if(A >= B){ l = mid + 1; } else{ r = mid - 1; } } return dp[z] = C; } int main(void){ ios_base::sync_with_stdio(0); cin.tie(0); ll k; cin>>k>>n; assert(k == 2); set<ll>ex; ll res = 0; f(i,0,n){ cin>>p[i]>>x[i]>>q[i]>>y[i]; ex.insert(x[i]); ex.insert(y[i]); if(p[i] != q[i]){ res++; } else{ res += abs(x[i] - y[i]); } } memset(dp,-1,sizeof dp); for(auto x:ex){ vale.pb(x); } vale.pb(1e9); ll l = 0,r = vale.size()-2; while(l <= r){ ll mid = (l+r)/2; ll a1 = 1e18,a2 = 1e18; f(j,max(0LL,mid-40),mid+1){ a1 = min(a1,evre(j)); } f(j,mid+1,min((ll)vale.size(),mid+10)){ a2 = min(a2,evre(j)); } if(a1 >= a2){ l = mid + 1; } else{ r = mid - 1; } } cout<<anss + res<<"\n"; bool ok = 1; bool ivra = 0; f(j,0,(ll)(vale.size()) - 1){ if(evre(j) < evre(j+1)){ ivra = 1; } if(evre(j) >= evre(j+1) && ivra){ ok = 0; } } assert(ok); } /* 2 5 B 0 A 4 B 1 B 3 A 5 B 7 B 2 A 6 B 1 A 7 */
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