제출 #1129307

#제출 시각아이디문제언어결과실행 시간메모리
1129307zhasyn원숭이와 사과 나무 (IZhO12_apple)C++20
0 / 100
98 ms17516 KiB
#include <bits/stdc++.h>
#define pb push_back
#define pf push_front
using namespace std;
#define F first
#define S second
typedef long long ll;
#define pii pair <int, int>
#define pll pair <ll, ll>
typedef long double ld;
const ll N = 2 * 1e6 + 100, M = 500 + 10, len = 315, inf = 1e18;
const ll mod = 998244353;
ll um(ll a, ll b){
	return (1LL * a * b) % mod;
}
ll subr(ll a, ll b){
	return ((1LL * a - b) % mod + mod) % mod;
}
ll bp(ll x, ll step){
	ll res = 1;
	while(step){
		if(step & 1) res = um(res, x);
		x = um(x, x);
		step /= 2;
	}
	return res;
}
ll inv(ll x){
	return bp(x, mod - 2);
}
// struct ver{
	// bool full;
	// ll p[2], ans;
// } a[N];
// 
// ll ct;
// ll create(){
	// ll x = ct++;
	// a[x].full = false;
	// a[x].p[0] = a[x].p[1] = -1;
	// a[x].ans = 0;
	// return x;
// }
int sz;
struct segtree {
	vector <int> tree;
	vector <bool> full;
	void init(ll n){
		sz = 1;
		while(sz < n){
			sz *= 2;
		}
		tree.assign(2 * sz - 1, 0);
		full.assign(2 * sz - 1, 0);
	}
	void prop(int x, int lx, int rx){
		if(rx - lx == 1) return;
		if(full[x]){
			full[2 * x + 1] = full[2 * x + 2] = 1;
			tree[2 * x + 1] = tree[2 * x + 2] = (rx - lx) / 2;
		}
	}
	void upd(int l, int r, int x = 0, int lx = 0, int rx = sz){
		prop(x, lx, rx);
		if(lx >= r || l >= rx) return;
		if(l <= lx && rx <= r){
			tree[x] = rx - lx;
			full[x] = true;
			return;
		}
		int mid = (lx + rx) / 2;
		upd(l, r, 2 * x + 1, lx, mid);
		upd(l, r, 2 * x + 2, mid, rx);
		if(full[x]) tree[x] = rx - lx;
		else{
			tree[x] = tree[2 * x + 1] + tree[2 * x + 2];
			if(tree[x] == rx - lx) full[x] = true;
		}
	}
	int get(int l, int r, int x = 0, int lx = 0, int rx = sz){
		prop(x, lx, rx);
		if(lx >= r || l >= rx) return 0LL;
		if(l <= lx && rx <= r) return tree[x];
		int mid = (lx + rx) / 2;
		int s1 = get(l, r, 2 * x + 1, lx, mid);
		int s2 = get(l, r, 2 * x + 2, mid, rx);
		return s1 + s2;
	}
};
int main() {
	//ios_base::sync_with_stdio(false);
	//cin.tie(nullptr);
	//cout.tie(nullptr);
	ll n, C = 0;
	cin >> n;
	segtree obj;
	//create();
	obj.init(2e6);
	for(ll i = 0, code, x, y; i < n; i++){
		cin >> code >> x >> y;
		x += C;
		y += C;
		if(code == 1){
			ll k = obj.get(x, y + 1);
			cout << k << endl;
			C = k;
		}
		else obj.upd(x, y + 1);
	}

  return 0;
}
#Verdict Execution timeMemoryGrader output
Fetching results...