제출 #1127418

#제출 시각아이디문제언어결과실행 시간메모리
1127418TymondColors (BOI20_colors)C++20
0 / 100
0 ms416 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; #define fi first #define se second #define vi vector<int> #define vll vector<long long> #define pii pair<int, int> #define pll pair<long long, long long> #define pb push_back #define mp make_pair #define eb emplace_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); mt19937_64 rng64(chrono::high_resolution_clock::now().time_since_epoch().count()); inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);} inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);} #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif struct custom_hash { static uint64_t splitmix64(uint64_t x) { x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; struct pair_hash{ size_t operator()(const pair<int,int>&x)const{ return hash<long long>()(((long long)x.first)^(((long long)x.second)<<32)); } }; int ask(ll k){ cout << "? " << k << endl; int res; cin >> res; return res; } int main(){ /*ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL);*/ ll n; cin >> n; ll C = 0LL; int B = 0; for(int k = 60; k >= 0; k--){ if((1LL << k) > n){ continue; } B = k; break; } ask((1LL << B)); if(!ask(1)){ C += (1LL << B); } ll l = 1LL; for(int k = B - 1; k >= 0; k--){ if((1LL << k) + C > n){ continue; } ll val = (1LL << k) + C; if(val == (1LL << B)){ ask(val + 1); if(!ask(2)){ C++; } }else{ if(!ask(val)){ C += (1LL << k); } } } cout << "= " << C << endl; return 0; }
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