제출 #1127168

#제출 시각아이디문제언어결과실행 시간메모리
1127168abushbandit_Mean (info1cup19_mean)C++20
100 / 100
9 ms584 KiB
//~ how can i make it 10% more fun? //~ what it would take for me to enjoy this? #include <bits/stdc++.h> using namespace std; #define int long long #define pb push_back #define all(x) x.begin(), x.end() #define ff first #define ss second template <class F, class _S> bool chmin(F &u, const _S &v){ bool flag = false; if ( u > v ){ u = v; flag |= true; } return flag; } template <class F, class _S> bool chmax(F &u, const _S &v){ bool flag = false; if ( u < v ){ u = v; flag |= true; } return flag; } int exp(int x, int n, int m) { x %= m; int res = 1; while (n > 0) { if (n & 1) { res = (res * x) % m; } x = (x * x) % m; n >>= 1; } return res; } int power(int x, int n) { int res = 1; while (n > 0) { if (n & 1) { res = res * x ; } x = x * x ; n >>= 1; } return res; } const int maxn = 2e5 + 1; const int mod = 1e9 + 7; const int inf = 1e18; void add(int &a, int b) { if (a + b >= mod) a = (a + b) - mod; else a += b; } void sub(int &a, int b) { if (a - b < 0) a = (a - b) + mod; else a -= b;; } template<typename T> using matrix = vector<vector<T>>; namespace FAST { template<typename T, typename F> istream &operator>>(istream &cin, pair<T, F> &p) { cin >> p.first >> p.second; return cin; } template<typename T, typename F> ostream &operator<<(ostream &cout, pair<T, F> &p) { cout << p.first << ' ' << p.second; return cout; } template<typename T> istream &operator>>(istream &cin, vector<T> &a) { for (T &i: a) cin >> i; return cin; } template<typename T> ostream &operator<<(ostream &cout, vector<T> &a) { for (T i: a) cout << i << ' '; return cout; } template<typename T> istream &operator>>(istream &cin, deque<T> &a) { for (T &i: a) cin >> i; return cin; } template<typename T> ostream &operator<<(ostream &cout, deque<T> &a) { for (T i: a) cout << i << ' '; return cout; } } using namespace FAST; int dp[201][201]; int a[201]; int f(int l, int r) { if(l == r) return a[l]; if(r - l + 1 == 2) return (a[l] + a[r]) / 2; if(dp[l][r]) return dp[l][r]; int ans = 0; for(int j = l + 1; j < r; j++) { chmax(ans, (f(l, j) + f(j + 1, r)) / 2); } chmax(ans, (f(l, r - 1) + a[r]) / 2); chmax(ans, (f(l + 1, r) + a[l]) / 2); return dp[l][r] = ans; } void solve() { int n; cin >> n; for(int i = 0;i < n;i++) cin >> a[i]; f(0, n - 1); cout << dp[0][n - 1]; } signed main() { ios_base::sync_with_stdio(0); cin.tie(0),cout.tie(0); int t = 1; //~ cin >> t; while(t--){ solve(); } }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...