Submission #1127168

#	Time	Username	Problem	Language	Result	Execution time	Memory
1127168		abushbandit_	Mean (info1cup19_mean)	C++20	100 / 100	9 ms	584 KiB

mean

//~ how can i make it 10% more fun?
//~ what it would take for me to enjoy this?

#include <bits/stdc++.h>

using namespace std;
 
#define int long long
#define pb push_back
#define all(x) x.begin(), x.end()
#define ff first
#define ss second
 
template <class F, class _S>
bool chmin(F &u, const _S &v){
    bool flag = false;
    if ( u > v ){
        u = v; flag |= true;
    }
    return flag;
}
 
template <class F, class _S>
bool chmax(F &u, const _S &v){
    bool flag = false;
    if ( u < v ){
        u = v; flag |= true;
    }
    return flag;
}
 
int exp(int x, int n, int m) {
	x %= m;
	int res = 1;
	while (n > 0) {
		if (n & 1) { res = (res * x) % m; }
		x = (x * x) % m;
		n >>= 1;
	}
	return res;
}
 
int power(int x, int n) {
	int res = 1;
	while (n > 0) {
		if (n & 1) { res = res * x ; }
		x = x * x ;
		n >>= 1;
	}
	return res;
}
 
const int maxn = 2e5 + 1;
 
const int mod = 1e9 + 7;
 
const int inf = 1e18;
 
void add(int &a, int b) {
    if (a + b >= mod) a = (a + b) - mod;
    else a += b;
}
 
void sub(int &a, int b) {
    if (a - b < 0) a = (a - b) + mod;
    else a -= b;;
}
 
template<typename T> using matrix = vector<vector<T>>;
 
namespace FAST {
    template<typename T, typename F>
    istream &operator>>(istream &cin, pair<T, F> &p) {
        cin >> p.first >> p.second;
        return cin;
    }
 
    template<typename T, typename F>
    ostream &operator<<(ostream &cout, pair<T, F> &p) {
        cout << p.first << ' ' << p.second;
        return cout;
    }
 
    template<typename T>
    istream &operator>>(istream &cin, vector<T> &a) {
		for (T &i: a) cin >> i;
        return cin;
    }
	
    template<typename T>
    ostream &operator<<(ostream &cout, vector<T> &a) {
        for (T i: a) cout << i << ' ';
        return cout;
    }
 
    template<typename T>
    istream &operator>>(istream &cin, deque<T> &a) {
        for (T &i: a) cin >> i;
        return cin;
    }
 
    template<typename T>
    ostream &operator<<(ostream &cout, deque<T> &a) {
        for (T i: a) cout << i << ' ';
        return cout;
    }
}
using namespace FAST;

int dp[201][201];
int a[201];

int f(int l, int r) {
	
	if(l == r) return a[l];
	if(r - l + 1 == 2) return (a[l] + a[r]) / 2;
	
	if(dp[l][r]) return dp[l][r];
 	
	int ans = 0;
	
	for(int j = l + 1; j < r; j++) {
		chmax(ans, (f(l, j) + f(j + 1, r)) / 2);
	}
	chmax(ans, (f(l, r - 1) + a[r]) / 2);
	chmax(ans, (f(l + 1, r) + a[l]) / 2);
	
	
	return dp[l][r] = ans;
	
}

void solve() {
	
	int n;
	cin >> n;
	
	for(int i = 0;i < n;i++) cin >> a[i];
	f(0, n - 1);
	cout << dp[0][n - 1];
	
} 

signed main() {
	
	ios_base::sync_with_stdio(0);
	cin.tie(0),cout.tie(0);
	
	int t = 1;
	//~ cin >> t;
	while(t--){
		solve();
	}
	
} 

• Subtask 1: 30 / 30
• Subtask 2: 70 / 70