제출 #1125361

#제출 시각아이디문제언어결과실행 시간메모리
1125361ljtunasBinaria (CCO23_day1problem1)C++20
18 / 25
129 ms57540 KiB
// author : anhtun_hi , nqg // 25-26.12.2024 #include <bits/stdc++.h> #define fi first #define se second #define all(x) x.begin(), x.end() #define reset(h, v) memset(h, v, sizeof h) #define Forv(i, a) for(auto& i : a) #define For(i, a, b) for(int i = a; i <= b; ++i) #define Ford(i, a, b) for(int i = a; i >= b; --i) #define c_bit(i) __builtin_popcountll(i) #define Bit(mask, i) ((mask >> i) & 1LL) #define onbit(mask, i) ((mask) bitor (1LL << i)) #define offbit(mask, i) ((mask) &~ (1LL << i)) #define Log2(x) (63 - __builtin_clzll(x)) #define TIME (1.0 * clock() / CLOCKS_PER_SEC) using namespace std; using ll = long long; using ii = pair<ll, ll>; using db = long double; using ull = unsigned long long; namespace std { template <typename T, int D> struct _vector : public vector <_vector <T, D - 1>> { static_assert(D >= 1, "Dimension must be positive!"); template <typename... Args> _vector(int n = 0, Args... args) : vector <_vector <T, D - 1>> (n, _vector <T, D - 1> (args...)) {} }; template <typename T> struct _vector <T, 1> : public vector <T> { _vector(int n = 0, const T& val = T()) : vector <T> (n, val) {} }; template <class A, class B> bool minimize(A &a, B b){return a > b ? a = b, true : false;} template <class A, class B> bool maximize(A &a, B b){return a < b ? a = b, true : false;} } const int dx[] = {0, 0, +1, -1}, dy[] = {-1, +1, 0, 0}, LOG = 20, base = 311, inf = 1e9 + 5; const int MAXN = 1e6 + 5; const ll mod = 1e6 + 3; const ll oo = 1e18; //#define int long long int n, k, a[MAXN]; namespace Mod{ inline void add(int &x, const int &y) { if((x += y) >= mod) x -= mod; } inline void sub(int &x, const int &y) { if((x -= y) < 0) x += mod; } inline void Mul(int &x, const int &y) { x = 1LL * x * y % mod; } inline int mul(const int &x, const int &y) { return 1LL * x * y % mod; } inline int sum(const int &x, const int &y) { int res = x + y; if(res >= mod) res -= mod; return res; } inline int diff(const int &x, const int &y) { int res = x - y; if(res < 0) res += mod; return res; } } using namespace Mod; namespace sub3{ int dp[1005][(1 << 10) + 5]; int solve(int i, int mask) { if (i > n) return 1; if (~dp[i][mask]) return dp[i][mask]; int res = 0; For(j, 0, 1){ int nmask = mask; nmask >>= 1; nmask |= j * (1 << (k - 1)); if (a[i] == c_bit(nmask)) (res += solve(i + 1, nmask)) %= mod; } return dp[i][mask] = res; } void Solve(){ memset(dp, -1, sizeof dp); int res = 0; For(mask, 0, (1 << k) - 1){ if (c_bit(mask) == a[k]) (res += solve(k + 1, mask)) %= mod; } cout << res << '\n'; } } long long Pow(long long a, long long n) { long long res = 1; while (n > 0) { if (n & 1) res = (res * a) % mod; a = (a * a) % mod, n >>= 1; } return res; } struct Ckn { long long fac[1000000+100], ifac[1000000+100]; void init(long long n) { fac[0] = 1; For(i, 1, n) fac[i] = (1ll * i * fac[i - 1]) % mod; ifac[n - 1] = Pow(fac[n - 1], mod - 2); Ford(i, n-2, 0) ifac[i] = (1ll * (i + 1) * ifac[i + 1]) % mod; } long long ckn(long long r, long long n){ if (n < r) return 0; return fac[n] * ifac[r] % mod * ifac[n - r] % mod; } // (k, n) = 0 if k > n // (k, n) = n * nf[k] * (k - 1, n - 1) // sigma (i, n) = 2 ^ n :i = 0 -> n // sigma (k, i) = (k + 1, n + 1) :i = 0 -> n // sigma (i, n + i) = (m, n + m + 1) :i = 0 -> m // sigma {(i, n) ^ 2} = (n, 2n) :i = 0 -> n // sigma {k * (k, n)} = n * 2 ^ (n - 1) :i = 1 -> n // x[1] + x[2] + .. + x[n] = m (x[i] >= 0) => (n - 1, m + n - 1) // x[1] + x[2] + .. + x[n] <= m (x[i] >= 0) => (n, m + n) // cell(u, v) -> cell(x, y) => (x - u, x + y - u - v) } C; namespace subfull{ vector<int> g[MAXN]; int f[MAXN], c[MAXN]; struct disjoint_set{ int par[MAXN]; void init() { For(i, 1, n) par[i] = -1; } int find(int u) { return (par[u] < 0) ? u : (par[u] = find(par[u])); } bool merge(int u, int v) { u = find(u), v = find(v); if (u == v) return false; if (par[u] > par[v]) swap(u, v); par[u] += par[v], par[v] = u; return true; } } dsu; void Solve(){ C.init(1e6); dsu.init(); For(i, 1, n - k + 1) f[i] = a[i + k - 1]; For(i, 1, n) c[i] = -1; For(i, 1, n - k){ if (abs(f[i] - f[i + 1]) > 1) {cout << 0; return;} if (f[i] == f[i + 1]){ dsu.merge(i, i + k); } } For(i, 1, n - k){ if (f[i] > f[i + 1]){ int u = dsu.find(i); int v = dsu.find(i + k); g[u].push_back(v); if (c[u] == 0) { cout << 0; return; } if (c[v] == 1) { cout << 0; return; } c[u] = 1; c[v] = 0; } else if (f[i] < f[i + 1]){ int u = dsu.find(i); int v = dsu.find(i + k); g[v].push_back(u); if (c[u] == 1) { cout << 0; return; } if (c[v] == 0) { cout << 0; return; } c[u] = 0; c[v] = 1; } } int ans = 1, cnt = 0; For(i, 1, k){ int u = dsu.find(i); if (c[u] == -1) ++cnt; f[1] -= (c[u] == 1); } cout << C.ckn(f[1], cnt) << '\n'; } } void Solve() { cin >> n >> k; For(i, k, n) cin >> a[i]; // sub3::Solve(); subfull::Solve(); } signed main() { cin.tie(0) -> sync_with_stdio(0); if(fopen("a.inp", "r")) { freopen("a.inp", "r", stdin); freopen("a.out", "w", stdout); } int t = 1; // cin >> t; while(t --) Solve(); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'int main()':
Main.cpp:200:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  200 |         freopen("a.inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~
Main.cpp:201:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  201 |         freopen("a.out", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
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