제출 #1122291

#제출 시각아이디문제언어결과실행 시간메모리
1122291TymondLet's Win the Election (JOI22_ho_t3)C++17
100 / 100
377 ms604 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; #define fi first #define se second #define vi vector<int> #define vll vector<long long> #define pii pair<int, int> #define pll pair<long long, long long> #define pb push_back #define mp make_pair #define eb emplace_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); mt19937_64 rng64(chrono::high_resolution_clock::now().time_since_epoch().count()); inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);} inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);} #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif struct custom_hash { static uint64_t splitmix64(uint64_t x) { x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; const int INF = 1e9; int n, m; vector<pii> a; bool comp(pii& x, pii& y){ if(x.se != y.se){ return x.se < y.se; } return x.fi < y.fi; } int main(){ ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL); cin >> n >> m; a.resize(n); for(int i = 0; i < n; i++){ cin >> a[i].fi >> a[i].se; if(a[i].se == -1){ a[i].se = INF; } } sort(all(a), comp); ld ans = (ld)INF; for(int k = 0; k <= m; k++){ vector<ld> dp(m - k + 1, (ld)INF); dp[0] = 0; ld p, val; for(int i = 0; i < n; i++){ for(int j = min(m - k, i + 1); j >= 0; j--){ p = dp[j]; if(j > 0){ val = (ld)dp[j - 1] + (ld)a[i].fi / (k + 1); }else{ val = (ld)INF; } if(i - j + 1 <= 0){ dp[j] = min(val, p); }else if(i - j + 1 > k){ dp[j] = min(val, p); }else{ dp[j] = min(val, (ld)p + (ld)a[i].se / (i - j + 1)); } } } ans = min(ans, dp[m - k]); } cout << fixed << setprecision(9); cout << ans<< '\n'; return 0; }
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