Submission #1113515

#TimeUsernameProblemLanguageResultExecution timeMemory
1113515jkb_gryzBubble Sort 2 (JOI18_bubblesort2)C++14
17 / 100
9063 ms7760 KiB
#include <bits/stdc++.h>
#include "bubblesort2.h"

using namespace std;
#define ll long long

const ll base = 1<<20;
const ll INF = 1e18+7;

ll tree[base<<1];
ll lazy[base<<1];
ll n;

void push(ll v){
    lazy[2*v] += lazy[v];
    lazy[2*v+1] += lazy[v];
    
    tree[2*v] += lazy[v];
    tree[2*v+1] += lazy[v];

    lazy[v] = 0;
}

ll p, k;
ll val;

void update(ll v, ll l, ll r){
    if(l > k || r < p) return;
    if(p <= l && r <= k){
        tree[v] += val;
        lazy[v] += val;
    }
    else{
        ll mid = (l+r)/2;

        push(v);

        update(2*v, l, mid);
        update(2*v+1, mid+1, r);

        tree[v] = max(tree[2*v], tree[2*v+1]);
    }
}

ll query(ll v, ll l, ll r){
    if(l > k || r < p) return -INF;
    if(p <= l && r <= k){
        return tree[v];
    }
    else{
        ll mid = (l+r)/2;

        push(v);

        auto lQ = query(2*v, l, mid);
        auto rQ = query(2*v+1, mid+1, r);
        return max(lQ, rQ);
    }
}


vector<int> countScans(vector<int> A, vector<int> X, vector<int> V){
    n = A.size();
	ll Q = X.size();
	vector<int> res(Q);

    map<long long, ll> skalowanie;
    for(auto i : A){
        skalowanie[i] = 0;
    }
    for(auto i : V){
        skalowanie[i] = 0;
    }
    ll id = 0;

    for(auto &i : skalowanie) i.second = ++id;
    
    for(ll i = 0; i < n; ++i){
        auto vi = A[i];
        p = 0, k = skalowanie[vi]-1;
        val = 1;
        update(1, 1, id);
    }
    
    for(ll i = 0; i < Q; ++i){
        p = 0, k = skalowanie[A[X[i]]]-1;
        val = -1;
        update(1, 1, id);

        A[X[i]] = V[i];

        p = 0, k = skalowanie[V[i]]-1;
        val = 1;
        update(1, 1, id);
        
        for(ll j = 0; j < n; ++j){
            p = k = skalowanie[A[j]];
            // cerr << query(1, 1, n) << " ";
            res[i] = max((ll)(res[i]), query(1, 1, id) - (n - j - 1));
        }
        // cerr << "\n";
    }

	return res;
}
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