제출 #1096106

#제출 시각아이디문제언어결과실행 시간메모리
1096106Tymond악어의 지하 도시 (IOI11_crocodile)C++17
46 / 100
3 ms2908 KiB
#include <bits/stdc++.h> #include "crocodile.h" using namespace std; using ll = long long; using ld = long double; #define fi first #define se second #define vi vector<int> #define vll vector<long long> #define pii pair<int, int> #define pll pair<long long, long long> #define pb push_back #define mp make_pair #define eb emplace_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); mt19937_64 rng64(chrono::steady_clock::now().time_since_epoch().count()); inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);} inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);} #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif struct custom_hash { static uint64_t splitmix64(uint64_t x) { x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; const int INF = 1e9; const int MAXN = 1e5 + 7; vector<pii> g[MAXN]; int vis[MAXN]; int f[MAXN]; int ans[MAXN]; int n, m; int dfs(int v, int parent){ vis[v] = 1; if(f[v]){ ans[v] = 0; return ans[v]; } ans[v] = INF; vi p; for(auto [u, c] : g[v]){ if(u == parent){ continue; } if(vis[u]){ p.pb(ans[u] + c); }else{ dfs(u, v); p.pb(ans[u] + c); } } sort(all(p)); if(sz(p) > 1){ ans[v] = min(ans[v], p[1]); } return ans[v]; } int travel_plan(int N, int M, int R[][2], int L[], int K, int P[]){ n = N; m = M; for(int i = 0; i < K; i++){ f[P[i]] = 1; } for(int i = 0; i < m; i++){ g[R[i][0]].pb({R[i][1], L[i]}); g[R[i][1]].pb({R[i][0], L[i]}); } return dfs(0, 0); } /*int main(){ int R[4][2] = {{0, 1}, {0, 2}, {3, 2}, {2, 4}}; int L[4] = {2, 3, 1, 4}; int P[3] = {1, 3, 4}; cout << travel_plan(5, 4, R, L, 3, P); return 0; }*/
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