Submission #1092825

#TimeUsernameProblemLanguageResultExecution timeMemory
1092825stefanopulosStone Arranging 2 (JOI23_ho_t1)C++17
100 / 100
122 ms14588 KiB
#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <bits/stdc++.h> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ldb; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef pair<ldb,ldb> pdd; #define ff(i,a,b) for(int i = a; i <= b; i++) #define fb(i,b,a) for(int i = b; i >= a; i--) #define trav(a,x) for (auto& a : x) #define sz(a) (int)(a).size() #define pb push_back #define fi first #define se second #define lb lower_bound #define ub upper_bound #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; // os.order_of_key(k) the number of elements in the os less than k // *os.find_by_order(k) print the k-th smallest number in os(0-based) const int mod = 1000000007; const int inf = 1e9 + 5; const int mxN = 200005; int n; int niz[mxN]; int R[mxN]; int main() { cin.tie(0)->sync_with_stdio(0); cin >> n; ff(i,1,n)cin >> niz[i]; map<int,int> last; fb(i,n,1){ int X = niz[i]; if(last.count(X))R[i] = last[X]; else last[X] = i; } ff(i,1,n){ if(R[i] == 0)continue; ff(j,i,R[i])niz[j] = niz[i]; i = R[i]; } ff(i,1,n)cout << niz[i] << " "; cout << '\n'; return 0; } /* 6 1 2 3 3 2 1 // probati bojenje sahovski */
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