제출 #1089582

#제출 시각아이디문제언어결과실행 시간메모리
1089582TymondPaths (BOI18_paths)C++17
100 / 100
241 ms162128 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; #define fi first #define se second #define vi vector<int> #define vll vector<long long> #define pii pair<int, int> #define pll pair<long long, long long> #define pb push_back #define mp make_pair #define eb emplace_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); mt19937_64 rng64(chrono::steady_clock::now().time_since_epoch().count()); inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);} inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);} #ifdef DEBUG auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";} auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";} #define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X) #else #define debug(...){} #endif struct custom_hash { static uint64_t splitmix64(uint64_t x) { x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; const int MAXN = 3e5 + 7; const int MAXK = (1 << 5) + 7; ll dp[MAXN][MAXK]; int in[MAXN][MAXK]; vi g[MAXN]; int a[MAXN]; int n, m, k; int main(){ ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL); cin >> n >> m >> k; for(int i =1; i <= n; i++){ cin >> a[i]; a[i]--; } for(int i = 1; i <= m; i++){ int u, v; cin >> u >> v; g[u].pb(v); g[v].pb(u); } queue<pii> q; for(int i = 1; i <= n; i++){ q.push({i, (1 << a[i])}); dp[i][(1 << a[i])] = 1LL; in[i][(1 << a[i])] = 1; } int v, msk; while(sz(q)){ v = q.front().fi; msk = q.front().se; q.pop(); for(auto u : g[v]){ if((1 << a[u]) & msk){ continue; } dp[u][msk | (1 << a[u])] += dp[v][msk]; if(!in[u][msk | (1 << a[u])]){ in[u][msk | (1 << a[u])] = 1; q.push({u, (msk | (1 << a[u]))}); } } } ll ans = -n; for(int i = 1; i <= n; i++){ for(int j = 1; j < (1 << k); j++){ ans = (ll)ans + dp[i][j]; } } cout << ans << '\n'; return 0; }
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