제출 #1089403

#제출 시각아이디문제언어결과실행 시간메모리
1089403vjudge1Growing Vegetable is Fun 3 (JOI19_ho_t3)C++17
0 / 100
228 ms704852 KiB
//#pragma GCC optimize ("O3") //#pragma GCC target ("sse4") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; #define ll long long #define ld long double #define ull unsigned long long #define pb push_back #define pob pop_back #define int long long #define int2 __int128_t #define Shrek_Crush228 ios_base::sync_with_stdio(0), cin.tie(0); #define F first #define S second #define FOR( i, x, n, d ) for( int i = x; i <= n; i += d ) #define FORR( i, x, n, d ) for( int i = x; i >= n; i -= d ) #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() #define no cout << "NO\n" #define yes cout << "YES\n" #define nep next_permutation #define sigma signed #define pii pair <int, int> using namespace std; string alp = "abcdefghijklmnopqrstuvwxyz"; string ae = "aoeiuy"; string nums = "123456789"; const int N = 300 + 123; const int inf = 1e18; const int MOD = 1e9 + 7; const int MOD1 = 998244353; const long long maxsum = 1e14; int a[N], b[N], c[N], l, r, n, m, w, sum, sum1, y, ans1, mx = -inf, mn = inf, ind, ind1, pref[N], suf[N]; string s, s1; ll ans, x; template<class T> using ordered_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>; struct RT { int sum, l, r, ind; }; int gcd( int a, int b ) { return ( b ? gcd( b, a % b ) : a ); } int lcm( int a, int b ) { return a / gcd( a, b ) * b; } int bp( int a, int b, int m ) { if( !b ) return 1; if( b & 1 ) return bp( a, b >> 1, m ) * bp( a, b >> 1, m ) % m * a % m; else return bp( a, b >> 1, m ) * bp( a, b >> 1, m ) % m; } struct po { int mn, sum, mx; }; int posr[N], posg[N], posy[N], pr[N], pg[N], py[N]; int dp[N][N][N][3]; void solve() { cin >> n >> s; int cntr = 0, cntg = 0, cnty = 0; FOR( i, 1, n, 1 ) { pr[i] = pr[i - 1], pg[i] = pg[i - 1], py[i] = py[i - 1]; if( s[i - 1] == 'R' ) cntr ++, posr[cntr] = i, pr[i] ++; if( s[i - 1] == 'G' ) cntg ++, posg[cntg] = i, pg[i] ++; if( s[i - 1] == 'Y' ) cnty ++, posy[cnty] = i, py[i] ++; } FOR( id, 0, n, 1 ) { FOR( R, 0, cntr, 1 ) { FOR( G, 0, cntg, 1 ) dp[id][R][G][0] = dp[id][R][G][1] = dp[id][R][G][2] = inf; } } dp[0][0][0][0] = dp[0][0][0][1] = dp[0][0][0][2] = 0; FOR( id, 1, n, 1 ) { FOR( R, 0, cntr, 1 ) { if( R > id ) break; FOR( G, 0, cntg, 1 ) { if( R + G > id ) break; int Y = id - R - G; if( cnty < Y ) continue; int pos0 = posr[R], cnt0 = cnty - ( py[pos0] ? py[pos0] : cnty ) + cntg - ( pg[pos0] ? pg[pos0] : cntg ), answ0 = max( 0ll, pos0 + cnt0 - id ); int pos1 = posg[G], cnt1 = cnty - ( py[pos1] ? py[pos1] : cnty ) + cntr - ( pr[pos1] ? pr[pos1] : cntr ), answ1 = max( 0ll, pos1 + cnt1 - id ); int pos2 = posy[Y], cnt2 = cntr - ( pr[pos2] ? pr[pos2] : cntr ) + cntg - ( pg[pos2] ? pg[pos2] : cntg ), answ2 = max( 0ll, pos2 + cnt2 - id ); //cout << id << ' ' << R << ' ' << G << ' ' << answ0 << ' ' << answ1 << ' ' << answ2 << '\n'; //cout << id << ' ' << R << ' ' << G << ' ' << pg[pos0] << '\n'; if( R ) dp[id][R][G][0] = min( dp[id - 1][R - 1][G][1], dp[id - 1][R - 1][G][2] ) + answ0; if( G ) dp[id][R][G][1] = min( dp[id - 1][R][G - 1][0], dp[id - 1][R][G - 1][2] ) + answ1; if( Y ) dp[id][R][G][2] = min( dp[id - 1][R][G][0], dp[id - 1][R][G][1] ) + answ2; } } } ans = min({ dp[n][cntr][cntg][0], dp[n][cntr][cntg][1], dp[n][cntr][cntg][2] }); if( ans == inf ) ans = -1; cout << ans; } sigma main() { //freopen("rmq.in", "r", stdin); //freopen("rmq.out", "w", stdout); Shrek_Crush228 int test = 1; if( !test ) cin >> test; while( test -- ) { solve(); } } // solved by KluydQ
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