이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#if _LOCAL
#include "tournament.h"
#endif
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int inf = int(1e9);
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> p2;
#define rep(i, high) for (int i = 0; i < high; i++)
#define repp(i, low, high) for (int i = low; i < high; i++)
#define repe(i, container) for (auto& i : container)
#define sz(container) ((int)container.size())
#define all(x) begin(x),end(x)
inline void fast() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); }
#if _LOCAL
#define assert(x) if (!(x)) __debugbreak()
#endif
struct fenwick
{
vi tree;
fenwick(int n) : tree(n+1) {}
void update(int i, int v)
{
for (i++; i < sz(tree); i += i & -i) tree[i] += v;
}
int query(int r)
{
int ret = 0;
for (r++; r > 0; r -= r & -r) ret += tree[r];
return ret;
}
int query(int l, int r) // [l,r]
{
if (l) l = query(l - 1);
return query(r) - l;
}
};
vi color;
p2 best=p2(-1, inf);
pair<int, p2> invalid = { -1,p2(-1,-1) };
pair<int,p2> dfs(int u, vvi& children)
{
if (sz(children[u]) == 0)
{
if (best.first == -1) best = p2(0, u);
if (best.first == 0 && u < best.second) best = p2(0, u);
return { color[u], p2(0, color[u]?u+1:u) };
}
assert(u != 586);
pair<int, p2> ret = { 0, p2(-1, -1) };
rep(i, sz(children[u]))
{
pair<int, p2> r = dfs(children[u][i], children);
assert(r.first < 31);
if (r == invalid) ret = invalid;
if (r.first)
{
if (i != 0) ret = invalid;
else ret = { 1, p2(r.second.first + 1,r.second.second) };
continue;
}
if (ret == invalid) continue;
if (r.second.first+1 > ret.second.first || (r.second.first+1==ret.second.first && r.second.second<ret.second.second))
{
ret = { ret.first, p2(r.second.first + 1,r.second.second) };
}
}
if (ret == invalid) return ret;
if (ret.second.first > best.first)
{
best = ret.second;
}
if (ret.second.first == best.first && ret.second.second < best.second)
{
best = ret.second;
}
return ret;
}
int GetBestPosition(int n, int c, int r, int *K, int *S, int *E)
{
fenwick tree(n);
rep(i, n) tree.update(i, 1);
vi s(c);
vi e(c);
vi k(n-1);
rep(i, n - 1) k[i] = K[i];
rep(i, c) s[i] = S[i];
rep(i, c) e[i] = E[i];
vi par(n+c);
vi leftmost_child(n+c,-1);
vi left_endpoint(n + c, inf);
vi nodes(n);
rep(i, n) nodes[i] = i;
rep(i, n) left_endpoint[i] = i;
rep(i, c)
{
int new_node = i + n;
int l = e[i] - s[i] + 1;
int u = -1;
rep(j, l)
{
int lo = -1;
int hi = n;
while (lo+1<hi)
{
int mid = (lo + hi) / 2;
if (tree.query(mid) >= s[i]+1)
{
hi = mid;
}
else lo = mid;
}
int v = nodes[hi];
tree.update(hi, -1);
par[v] = new_node;
left_endpoint[par[v]] = min(left_endpoint[par[v]], left_endpoint[v]);
u = hi;
}
assert(u != -1);
nodes[u] = new_node;
tree.update(u, 1);
}
vvi children(n+c);
rep(i, sz(par) - 1) children[par[i]].push_back(i);
rep(i, sz(children)) sort(all(children[i]), [&](int i, int j)
{
return left_endpoint[i] < left_endpoint[j];
});
color.resize(n);
rep(i, n - 1) color[i + 1] = k[i] > r;
dfs(sz(par)-1, children);
return best.second;
}
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