제출 #1082330

#제출 시각아이디문제언어결과실행 시간메모리
1082330GrindMachinePainting Squares (IOI20_squares)C++17
0 / 100
2 ms1024 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(...) 42 #endif /* refs: https://codeforces.com/blog/entry/82625 https://www.baeldung.com/cs/de-bruijn-sequence (de bruijn sequence) */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "squares.h" std::vector<int> paint(int n) { // std::vector<int> labels(n + 1, 1); // return labels; int k = 10; vector<vector<pii>> adj(1<<(k-1)); rep(u,1<<(k-1)){ int d = 0; for(auto v : {u<<1,u<<1|1}){ adj[u].pb({v%(1<<(k-1)),d}); d++; } } vector<int> ord; auto dfs = [&](int u, auto &&dfs) -> void{ while(!adj[u].empty()){ auto [v,c] = adj[u].back(); adj[u].pop_back(); ord.pb(u<<1|c); dfs(v,dfs); } }; dfs(0,dfs); vector<int> a(1<<k); rep(i,1<<k){ int b = k-1; for(int j = i; b; j = (j+1)%(1<<k), --b){ if(ord[i]&(1<<b)){ a[j] = 1; } } } while(sz(a) > n) a.pop_back(); a.pb(10); return a; } int find_location(int n, std::vector<int> c) { string res = "1010101110001111000111011110110000011111010011100110111000001110001000010110000101101110011001100010110101001011000001011110110110010000010100011100111000101111110001100010001100111100000001000001000100111110010001111110010010101000101001110111110010101011101110001101000001110110111110100011110011111110101010001101101111010101101111110100101111100110101000100000010101100001110000010011010000100011110100100010010111000101001010010011001001110000111010010101010011011000010000000000011010001011110010011110110101101010101101011110001101111111110011001010111001011110000110110001100101110110101000001100100011000010100000011001110100000010010110101100110110011001111100001001100110111100000110111001000101100101000100100011101011111011011101000011010011101011001001100011010110001010110100100000001111001000011110101001001001101101011101001100101100111101011110111111101100011100101011001011010001001101110110110110100111101000010101110101000010111011110011000010010000110000111110011101100010011100"; // found by simulated annealing vector<int> a(n); rep(i,n) a[i] = res[i]-'0'; int k = 10; int cnt = count(all(c),-1); if(cnt){ return n+cnt-k; } rep(i,n){ if(i+k-1 >= n) break; bool ok = true; rep(j,k){ if(a[i+j] != c[j]){ ok = false; break; } } if(ok){ return i; } } assert(0); return -1; }
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