Submission #107832

# Submission time Handle Problem Language Result Execution time Memory
107832 2019-04-26T01:56:50 Z cki86201 흑백 이미지 찾기 (kriii3_G) C++11
0 / 101
182 ms 20416 KB
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <memory.h>
#include <math.h>
#include <assert.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <string>
#include <algorithm>
#include <iostream>
#include <functional>
#include <unordered_set>
#include <bitset>
#include <time.h>
#include <limits.h>
 
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define Fi first
#define Se second
#define pb push_back
#define szz(x) (int)x.size()
#define rep(i,n) for(int i=0;i<n;i++)
#define all(x) x.begin(),x.end()
typedef tuple<int, int, int> t3;
 
#include <complex>
typedef long double ldouble;
namespace FFT{
	// blog.myungwoo.kr/54
	typedef complex<ldouble> base;
	typedef long long ll;
	
#define sz(x) ((int)(x).size())
 
	const ldouble C_PI = acosl(-1);
 
	void fft(vector <base> &a, bool invert){
		int n = sz(a);
		for(int i=0,j=0;i<n;++i) {
			if(i>j) swap(a[i],a[j]);
			for(int k=n>>1;(j^=k)<k;k>>=1);
		}
		for (int len=2;len<=n;len<<=1){
			ldouble ang = 2*C_PI/len*(invert?-1:1);
			base wlen(cosl(ang), sinl(ang));
			for (int i=0;i<n;i+=len){
				base w(1);
				for (int j=0;j<len/2;j++){
					if((j & 31) == 31)w = base(cosl(ang * j), sinl(ang * j));	//오차가 클 경우 이 빈도를 늘린다. cos, sin 함수는 시간 부담이 있으니 주의
					base u = a[i+j], v = a[i+j+len/2]*w;
					a[i+j] = u+v;
					a[i+j+len/2] = u-v;
					w *= wlen;
				}
			}
		}
		if (invert){
			for (int i=0;i<n;i++) a[i] /= n;
		}
	}
 
	void multiply(const vector<int> &a,const vector<int> &b,vector<int> &res, const int MOD){
		vector <base> fa(all(a)), fb(all(b));
		int n = 1;
		while (n < max(sz(a),sz(b))) n <<= 1; n <<= 1;
		fa.resize(n); fb.resize(n);
		fft(fa,false); fft(fb,false);
		for (int i=0;i<n;i++) fa[i] *= fb[i];
		fft(fa,true);
		res.resize(n);
		for (int i=0;i<n;i++) res[i] = ((ll)(fa[i].real()+(fa[i].real()>0?0.5:-0.5))) % MOD;
	}
 
	void multiply_big(const vector<int> &a,const vector<int> &b, vector <ll> &res){
		// 단순히 오차가 심해 구하지 못하는 경우
		// 결과값은 long long 범위 안
		int n = 1;
		while (n < max(sz(a),sz(b))) n <<= 1; n <<= 1;
		vector <base> A(n), B(n);
		int L_BLOCK = 10;
		for(int i=0;i<n;i++) A[i] = (i < sz(a) ? base(a[i] & ((1<<L_BLOCK)-1), a[i] >> L_BLOCK) : base(0));
		for(int i=0;i<n;i++) B[i] = (i < sz(b) ? base(b[i] & ((1<<L_BLOCK)-1), b[i] >> L_BLOCK) : base(0));
		fft(A, false); fft(B, false);
		vector <base> f1(n), f2(n), f3(n), f4(n);
		for(int i=0;i<n;i++) {
			int j=(n-i)&(n-1);
			f2[i]=(A[i]+conj(A[j]))*base(0.5,0);
			f1[i]=(A[i]-conj(A[j]))*base(0,-0.5);
			f4[i]=(B[i]+conj(B[j]))*base(0.5,0);
			f3[i]=(B[i]-conj(B[j]))*base(0,-0.5);
		}
		for(int i=0;i<n;i++) {
			A[i]=f1[i]*f3[i]+f1[i]*f4[i]*base(0,1);
			B[i]=f2[i]*f4[i]*base(0,1)+f2[i]*f3[i];
		}
		fft(A, true); fft(B, true);
		res.resize(n);
		for(int i=0;i<n;i++) {
			ll g1=(ll)(A[i].real()+0.5);
			ll g2=(ll)(A[i].imag()+0.5);
			ll g3=(ll)(B[i].real()+0.5);
			ll g4=(ll)(B[i].imag()+0.5);
			res[i] = (g4 + ((g2+g3)<<(L_BLOCK)) + (g1<<(L_BLOCK<<1)));
		}
	}
}
 
int N, M, R, C;
int A[1010][1010], B[1010][1010];
ll Sx[1010][1010], Sxx[1010][1010];
 
vector <int> va, vb;
vector <ll> res;
 
ll get_s(ll T[1010][1010], int x1, int y1, int x2, int y2) {
	return T[x2][y2] - T[x2][y1-1] - T[x1-1][y2] + T[x1-1][y1-1];
}
 
#define i128 __int128
 
int main() {
	scanf("%d%d", &N, &M);
	for(int i=1;i<=N;i++) for(int j=1;j<=M;j++) scanf("%d", A[i] + j);
	for(int i=1;i<=N;i++) for(int j=1;j<=M;j++) {
		Sx[i][j] = Sx[i-1][j] + Sx[i][j-1] - Sx[i-1][j-1] + A[i][j];
		Sxx[i][j] = Sxx[i-1][j] + Sxx[i][j-1] - Sxx[i-1][j-1] + (ll)A[i][j] * A[i][j];
	}
	scanf("%d%d", &R, &C);
	for(int i=1;i<=R;i++) for(int j=1;j<=C;j++) scanf("%d", B[i] + j);
	for(int i=1;i<=N;i++) for(int j=1;j<=M;j++) if(A[i][j] < 0) exit(0);
	for(int i=1;i<=R;i++) for(int j=1;j<=C;j++) if(B[i][j] < 0) exit(0);
  if(N > 100 || M > 100) return 0;
	ll sy = 0, syy = 0;
	for(int i=1;i<=R;i++) for(int j=1;j<=C;j++) {
		sy += B[i][j];
		syy += (ll) B[i][j] * B[i][j];
	}
	for(int i=1;i<=N;i++) for(int j=1;j<=M;j++) va.pb(A[i][j]);
	for(int i=R;i;i--) {
		for(int j=C;j;j--) vb.pb(B[i][j]);
		rep(j, M - C) vb.pb(0);
	}
	FFT::multiply_big(va, vb, res);
	int ans = 0;
	ll prs[3] = {1000000000000000003ll, 1000000000000000009ll, 1000000000000000031ll};
	for(int i=R;i<=N;i++) for(int j=C;j<=M;j++) {
		ll sxy = res[(i-1)*M+(j-1)];
		if(N <= 100 && M <= 100) {
			sxy = 0;
			rep(a, R) rep(b, C) sxy += (ll) A[i-a][j-b] * B[R-a][C-b];
		}
		ll sx = get_s(Sx, i-R+1, j-C+1, i, j);
		ll sxx = get_s(Sxx, i-R+1, j-C+1, i, j);
		ll n = R * C;
		if((i128)sx * sx == (i128)n * sxx) {
			if((i128)sy * sy == (i128)n * syy) ++ans;
		}
		else {
			int ok = 1;
			rep(u, 3) {
				ll mod = prs[u];
				i128 val = (i128)syy * (((i128)n * sxx - (i128)sx * sx) % mod) % mod;
				val = (val - (i128) sxy * sxy % mod * n) % mod; if(val < 0) val += mod;
				val = (val - (i128) sxx * sy % mod * sy) % mod; if(val < 0) val += mod;
				val = (val + (i128) 2 * sxy * sx % mod * sy) % mod;
				if(val != 0) ok = 0;
			}
			ans += ok;
		}
	}
	printf("%d\n", ans);
	return 0;
}

Compilation message

G.cpp: In function 'void FFT::multiply(const std::vector<int>&, const std::vector<int>&, std::vector<int>&, int)':
G.cpp:71:3: warning: this 'while' clause does not guard... [-Wmisleading-indentation]
   while (n < max(sz(a),sz(b))) n <<= 1; n <<= 1;
   ^~~~~
G.cpp:71:41: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'while'
   while (n < max(sz(a),sz(b))) n <<= 1; n <<= 1;
                                         ^
G.cpp: In function 'void FFT::multiply_big(const std::vector<int>&, const std::vector<int>&, std::vector<long long int>&)':
G.cpp:84:3: warning: this 'while' clause does not guard... [-Wmisleading-indentation]
   while (n < max(sz(a),sz(b))) n <<= 1; n <<= 1;
   ^~~~~
G.cpp:84:41: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'while'
   while (n < max(sz(a),sz(b))) n <<= 1; n <<= 1;
                                         ^
G.cpp: In function 'int main()':
G.cpp:128:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d", &N, &M);
  ~~~~~^~~~~~~~~~~~~~~~
G.cpp:129:51: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for(int i=1;i<=N;i++) for(int j=1;j<=M;j++) scanf("%d", A[i] + j);
                                              ~~~~~^~~~~~~~~~~~~~~~
G.cpp:134:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d", &R, &C);
  ~~~~~^~~~~~~~~~~~~~~~
G.cpp:135:51: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for(int i=1;i<=R;i++) for(int j=1;j<=C;j++) scanf("%d", B[i] + j);
                                              ~~~~~^~~~~~~~~~~~~~~~
# Verdict Execution time Memory Grader output
1 Correct 72 ms 8184 KB Output is correct
2 Correct 118 ms 8184 KB Output is correct
3 Correct 93 ms 8188 KB Output is correct
4 Correct 87 ms 8296 KB Output is correct
5 Correct 89 ms 8312 KB Output is correct
6 Correct 98 ms 8332 KB Output is correct
7 Correct 88 ms 8304 KB Output is correct
8 Correct 113 ms 8284 KB Output is correct
9 Correct 91 ms 8324 KB Output is correct
10 Correct 112 ms 8372 KB Output is correct
11 Correct 83 ms 8308 KB Output is correct
12 Correct 87 ms 8312 KB Output is correct
13 Correct 88 ms 8312 KB Output is correct
14 Correct 93 ms 8336 KB Output is correct
15 Correct 90 ms 8412 KB Output is correct
16 Correct 91 ms 8284 KB Output is correct
17 Correct 86 ms 8316 KB Output is correct
18 Correct 83 ms 8312 KB Output is correct
19 Incorrect 5 ms 1664 KB Output isn't correct
20 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Incorrect 182 ms 20416 KB Output isn't correct
2 Halted 0 ms 0 KB -