이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("O3,unroll-loops,Ofast")
//#pragma GCC target("avx2,bmi,bmi2,popcnt,lzcnt")
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
//using namespace __gnu_pbds;
#define MAX 200007
#define pb push_back
#define mp make_pair
#define int long long
#define f first
#define s second
#define vi vector<int>
#define pii pair<int,int>
#define si set<int>
#define vpii vector<pair<int,int>>
const int mod = 1e9+7;
const int INF = 1e18;
// myMap.begin()->first : key
// myMap.begin()->second : value
int epow(int a,int b){int ans=1;while(b){if(b&1) ans*=a;a*=a;;b>>=1;}return ans;}
int gcd(int a,int b) {if(a<b)swap(a,b);while(b){int tmp=b;b=a%b;a=tmp;}return a;}
int mul(int a,int b){return ((a%mod)*(b%mod))%mod;}
int sum(int a,int b){return ((a%mod)+(b%mod))%mod;}
//typedef tree<pii,null_type,less<pii>,rb_tree_tag,tree_order_statistics_node_update>ordered_set;
void solve(){
int n,m,k,a,b; cin>>n>>m>>k>>a>>b;
vector<vi> adj(n+1);
for(int i=0;i<m;i++){
int x,y; cin>>x>>y;
adj[x].pb(y); adj[y].pb(x);
}
vi used(n+5),dist(n+5,INF); dist[k]=0;
queue<int> q; q.push(k);
while(q.size()){
auto node = q.front();
q.pop();
used[node]=true;
for(auto u : adj[node]){
if(used[u]) continue;
if(dist[u]>dist[node]+1)
{q.push(u); dist[u]=dist[node]+1;}
}
}
for(int i=1;i<=n;i++) sort(adj[i].begin(),adj[i].end());
vector<vi> adj2=adj;
vi dist1(n+5,INF),vis(n+5); dist1[k]=0; vis[k]=true;
q.push(k);
while(q.size()){
int node = q.front();
q.pop();
// if(dist[node.s]!=node.f) continue;
for(auto nxt1 : adj[node]){
for(auto nxt2 : adj2[nxt1]){
if(vis[nxt2]) continue;
if (binary_search(adj[node].begin(), adj[node].end(), nxt2))
continue;
dist1[nxt2]=dist1[node]+1;
vis[nxt2]=true;
q.push(nxt2);
}
/* vi v;
for(auto nxt2:adj2[nxt1]){
if(vis[nxt2]==false) v.pb(nxt2);
swap(adj2[nxt1],v);
} */
}
}
// for(int i=1;i<=n;i++) cout<<dist[i]<<"\n";;
for(int i=1;i<=n;i++){
if(dist[i]%2) cout<<min({dist[i]*a,(dist[i]/2)*b+a,dist1[i]*b})<<endl;
else cout<<min(dist[i]*a,(dist[i]/2)*b)<<endl;
}
return;
}
int32_t main() {
// freopen("hayfeast.in", "r", stdin);
// freopen("hayfeast.out", "w", stdout);
ios_base::sync_with_stdio(0);cin.tie(0);
int t=1;
// cin >> t;
while (t--) solve();
return 0;
}
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