Submission #1063795

#	Time	Username	Problem	Language	Result	Execution time	Memory
1063795		sleepntsheep	Alice, Bob, and Circuit (APIO23_abc)	C++17	8 / 100	100 ms	10192 KiB

abc

#include "abc.h"
#include <array>
using namespace std;

// you may find the definitions useful
const int OP_ZERO    = 0;  // f(OP_ZERO,    x0, x1) = 0
const int OP_NOR     = 1;  // f(OP_NOR,     x0, x1) = !(x0 || x1)
const int OP_GREATER = 2;  // f(OP_GREATER, x0, x1) = (x0 > x1)
const int OP_NOT_X1  = 3;  // f(OP_NOT_X1,  x0, x1) = !x1
const int OP_LESS    = 4;  // f(OP_LESS,    x0, x1) = (x0 < x1)
const int OP_NOT_X0  = 5;  // f(OP_NOT_X0,  x0, x1) = !x0
const int OP_XOR     = 6;  // f(OP_XOR,     x0, x1) = (x0 ^ x1)
const int OP_NAND    = 7;  // f(OP_NAND,    x0, x1) = !(x0 && x1)
const int OP_AND     = 8;  // f(OP_AND,     x0, x1) = (x0 && x1)
const int OP_EQUAL   = 9;  // f(OP_EQUAL,   x0, x1) = (x0 == x1)
const int OP_X0      = 10; // f(OP_X0,      x0, x1) = x0
const int OP_GEQ     = 11; // f(OP_GEQ,     x0, x1) = (x0 >= x1)
const int OP_X1      = 12; // f(OP_X1,      x0, x1) = x1
const int OP_LEQ     = 13; // f(OP_LEQ,     x0, x1) = (x0 <= x1)
const int OP_OR      = 14; // f(OP_OR,      x0, x1) = (x0 || x1)
const int OP_ONE     = 15; // f(OP_ONE,     x0, x1) = 1


// Alice
int // returns la
alice(
    /*  in */ const int n,
    /*  in */ const char names[][5],
    /*  in */ const unsigned short numbers[],
    /* out */ bool outputs_alice[]
    ) {
  for (int j = 0; j < 16; ++j)
    outputs_alice[j] = (numbers[0] >> j) & 1;
  return 16;
}


// Bob
int // returns lb
bob(
    /*  in */ const int m,
    /*  in */ const char senders[][5],
    /*  in */ const char recipients[][5],
    /* out */ bool outputs_bob[]
   ) {
  for (int j = 0; j < 16; ++j)
    outputs_bob[j] = ((m >> j) & 1);
  return 10;
}


// Circuit
int // returns l
circuit(
    /*  in */ const int la,
    /*  in */ const int lb,
    /* out */ int operations[],
    /* out */ int operands[][2],
    /* out */ int outputs_circuit[][16]
    ) {
  int x = la + lb;
  array<int, 1001> num;

  auto put = [&](int type, int o1, int o2) {
    operations[x] = type;
    operands[x][0] = o1;
    operands[x][1] = o2;
    return x++;
  };

  for (int i = 0; i <= 1000; ++i) {
    num[i] = x;
    for (int j = 0; j < 10; ++j)
      operations[x++] = ((i >> j) & 1) ? OP_ONE: OP_ZERO;
  }

  auto leq = [&](int i, int j, int bit) {
    int l0 = put(OP_LESS, num[0], num[0]);
    for (int I = i + bit - 1, J = j + bit - 1; I >= i; --I, --J) {
      int l1 = put(OP_LESS, I, J);
      l0 = put(OP_OR, l0, l1);
    }
    return l0;
  };

  auto cmpr = leq(num[0], la, 10);
  for (int j = 0; j < 16; ++j)
    outputs_circuit[0][j] = put(OP_AND, cmpr, j);
  return x;
}

• Subtask 1: 4 / 4
• Subtask 2: 4 / 4
• Subtask 3: 0 / 4
• Subtask 4: 0 / 24
• Subtask 5: 0 / 24
• Subtask 6: 0 / 6
• Subtask 7: 0 / 18
• Subtask 8: 0 / 10
• Subtask 9: 0 / 6