oj.uz

Submission #106123

# Submission time Handle Problem Language Result Execution time Memory
106123 2019-04-16T16:51:55 Z cki86201 JOIRIS (JOI16_joiris) C++11
0 / 100
 2 ms 384 KB 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <memory.h>
#include <math.h>
#include <assert.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <string>
#include <algorithm>
#include <iostream>
#include <functional>
#include <unordered_set>
#include <bitset>
#include <time.h>
#include <limits.h>

using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define Fi first
#define Se second
#define pb push_back
#define szz(x) (int)x.size()
#define rep(i,n) for(int i=0;i<n;i++)
#define all(x) x.begin(),x.end()
typedef tuple<int, int, int> t3;

int N, K;
int A[55];
ll X[5050];
int H[55];
ll FULL;

vector <pii> ans;

void erase(int x) {
	int mxh = -1;
	for(int i=1;i<=N;i++) mxh = max(mxh, H[i]);
	for(int i=x;i<mxh;i++) X[i] = X[i+1];
	X[mxh] = 0;
}

void fix_h() {
	for(int i=1;i<=N;i++) {
		while(H[i] > 0 && !(X[H[i]] & 1LL << i)) --H[i];
	}
}

void put(int vert, int x) {
	ans.pb(pii(vert, x));
	if(vert == 2) {
		for(int i=x;i<x+K;i++) A[i] += 1;
		
		int mx = -1;
		for(int i=x;i<x+K;i++) mx = max(mx, H[i]);
		for(int i=x;i<x+K;i++) H[i] = mx + 1;
		X[mx + 1] += 1LL << (x + K);
		X[mx + 1] -= 1LL << x;
		if(X[mx + 1] == FULL) {
			erase(mx + 1);
			fix_h();
		}
	}
	else {
		A[x] += K;
		
		int h = H[x];
		for(int i=h+1;i<=h+K;i++) X[i] |= 1LL << x;
		H[x] += K;
		for(int a=0, i=h+1;a<K;a++) {
			if(X[i] == FULL) {
				erase(i);
				fix_h();
			}
			else ++i;
		}
	}
}

void print() {
	for(int i=1;i<=N;i++) printf("%d", H[i]); puts("");
	int mxh = -1;
	for(int i=1;i<=N;i++) mxh = max(mxh, H[i]);
	for(int i=mxh;i;i--) {
		for(int j=1;j<=N;j++) {
			printf("%c", (X[i] & 1LL << j) ? 'O' : '.');
		} puts("");
	}
}

int main() {
	scanf("%d%d", &N, &K);
	FULL = (1LL << (N + 1)) - 2;
	for(int i=1;i<=N;i++) scanf("%d", A + i);
	if(N % K != 0) return 0;
	for(int i=1;i<=N;i++) {
		H[i] = A[i];
		for(int j=1;j<=A[i];j++) X[j] |= 1LL << i;
	}
	int sum[55] = {};
	for(int i=1;i<=N;i++) sum[i % K] += A[i];
	for(int i=1;i<K;i++) if(sum[0] != sum[i]) {
		puts("-1");
		return 0;
	}
	
	for(int i=N-1;i;i--) while(A[i] < A[i+1]) {
		put(1, i);
	}
	int tar = (A[1] + K - 1) / K * K;
	for(int i=1;i+K-1<=N;i++) {
		while(A[i] < tar) put(2, i);
	}
	for(int i=N-K+2;i<=N;i++) {
		while(A[i] < tar) put(1, i);
	}
	while(1) {
		int mxh = -1;
		for(int i=1;i<=N;i++) mxh = max(mxh, H[i]);
		if(mxh == 0) break;
		int f = -1;
		for(int i=1;i<=N;i++) if(!(1LL<<i & X[mxh])) {
			if(f == -1 || H[f] > H[i]) f = i;
		}
		put(1, f);
	}
	printf("%d\n", szz(ans));
	for(pii e : ans) printf("%d %d\n", e.Fi, e.Se);
	
	return 0;
}

Compilation message

joiris.cpp: In function 'void print()':
joiris.cpp:85:2: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
  for(int i=1;i<=N;i++) printf("%d", H[i]); puts("");
  ^~~
joiris.cpp:85:44: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  for(int i=1;i<=N;i++) printf("%d", H[i]); puts("");
                                            ^~~~
joiris.cpp: In function 'int main()':
joiris.cpp:96:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d", &N, &K);
  ~~~~~^~~~~~~~~~~~~~~~
joiris.cpp:98:29: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for(int i=1;i<=N;i++) scanf("%d", A + i);
                        ~~~~~^~~~~~~~~~~~~

Subtask #1
0 / 15.0

# Verdict Execution time Memory Grader output
1 Correct 2 ms 256 KB Output is correct
2 Correct 2 ms 256 KB Output is correct
3 Correct 2 ms 384 KB Output is correct
4 Incorrect 2 ms 256 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
0 / 15.0

# Verdict Execution time Memory Grader output
1 Incorrect 2 ms 256 KB Unexpected end of file - int32 expected
2 Halted 0 ms 0 KB -

Subtask #3
0 / 15.0

# Verdict Execution time Memory Grader output
1 Correct 2 ms 256 KB Output is correct
2 Correct 2 ms 256 KB Output is correct
3 Correct 2 ms 384 KB Output is correct
4 Incorrect 2 ms 256 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #4
0 / 55.0

# Verdict Execution time Memory Grader output
1 Correct 2 ms 256 KB Output is correct
2 Correct 2 ms 256 KB Output is correct
3 Correct 2 ms 384 KB Output is correct
4 Incorrect 2 ms 256 KB Output isn't correct
5 Halted 0 ms 0 KB -