제출 #1059908

#제출 시각아이디문제언어결과실행 시간메모리
1059908ewirlan자동 인형 (IOI18_doll)C++17
100 / 100
63 ms9024 KiB
// #ifndef __SIZEOF_INT128__ #define __SIZEOF_INT128__ #endif #pragma GCC optimize("Ofast") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace chrono; using namespace __gnu_pbds; template <typename T> using oset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>; #define rep(i, p, k) for(int i(p); i < (k); ++i) #define per(i, p, k) for(int i(p); i > (k); --i) #define sz(x) (int)(x).size() #define sc static_cast typedef long long ll; typedef long double ld; typedef unsigned int uint; typedef unsigned long long ull; typedef __int128_t lll; //#define int ll template <typename T = int> using par = std::pair <T, T>; #define fi first #define se second #define test int _number_of_tests(in()); while(_number_of_tests--) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define pb emplace_back struct Timer { string name{""}; time_point<high_resolution_clock> end, start{high_resolution_clock::now()}; duration<float, std::milli> dur; Timer() = default; Timer(string nm): name(nm) {} ~Timer() { end = high_resolution_clock::now(); dur= end - start; cout << "@" << name << "> " << dur.count() << " ms" << '\n'; } }; template <typename T = int> inline T in() { static T x; std::cin >> x; return x; } std::string yn(bool b) { if(b) return "YES\n"; else return "NO\n"; } template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par); template <typename T> std::ostream& operator<< (std::ostream& out, const std::vector <T>& wek) { for(const auto& i : wek)out << i << ' '; return out; } template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par) { out << '{'<<par.first<<", "<<par.second<<"}"; return out; } #define show(x) cerr << #x << " = " << x << '\n'; #include "doll.h" void create_circuit(int m, vector <int> a) { a.pb(0); vector <int> c(m+1, -1); vector <int> x{0}, y{0}; int d(1), p(0); while(d < sz(a)){ d *= 2; ++p; } vector <int> v(d, -1); int ind(0); rep(i, 0, d){ int j(0); rep(k, 0, p)if(i&1<<k)j |= 1<<(p-1-k); v[j] = (j < (d-sz(a)) ? -1 : a[ind++]); } while(d > 2){ d /= 2; --p; vector <int> w(d); rep(i, 0, d){ if(v[2*i] == v[2*i+1])w[i] = v[2*i]; else{ x.pb(v[2*i]); y.pb(v[2*i+1]); w[i] = -sz(x); } } // cerr << v << '\n'; v = w; } // cerr << v << '\n'; x[0] = v[0]; y[0] = v[1]; // cerr << '{' << c << "} "; // cerr << '{' << x << "} "; // cerr << '{' << y << "} "; // cerr << '\n'; answer(c, x, y); }
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