제출 #1052536

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1052536		dozer	비스킷 담기 (IOI20_biscuits)	C++14	35 / 100	5 ms	860 KiB

biscuits

#include "biscuits.h"
#include<bits/stdc++.h>
using namespace std;
#define fileio() freopen("input.txt", "r", stdin), freopen("output.txt", "w", stdout)
#define fastio() cin.tie(0), ios_base::sync_with_stdio(0)
#define sp " "
#define endl "\n"
#define pii pair<int, int>
#define st first
#define nd second
#define pb push_back
#define ll long long
#define LL node * 2
#define RR node * 2 + 1
#define N 130

const int modulo = 1e9 + 7;
const ll M = 1e18;




long long count_tastiness(long long x, vector<long long> a) {
	int n = a.size();
	
	for (int i = 0; i < (int)a.size(); i++){
		if (a[i] > x + 1){
			if (i < n - 1) a[i + 1] += (a[i] - x) / 2;
			else a.pb((a[i] - x) / 2);
			a[i] = a[i] - ((a[i] - x) / 2) * 2;
		}
	}
	while(a.size() < N) a.pb(0);

	int m = a.size();
	vector<double> pre(m);
	vector<double> pw(m, 1);
	for (int i = 1; i < m; i++) pw[i] = pw[i - 1] * 2;

	pre[0] = a[0];
	for (int i = 1; i < m; i++){
		pre[i] = pre[i - 1] + (double)a[i] * pw[i];
	}


	vector<double> maks(m);
	vector<ll> dp(m, 0);
	
	for (int i = 0; i < m; i++) {
		maks[i] = floor((pre[i] / x) + 1);
	}
	for (int i = 0; i < m; i++){
		dp[i] = 0;
		if (i == 0){
			dp[i] = (ll)maks[i];
			continue;
		}

		double tmp = maks[i];
		for (int j = i - 1; j >= 0; j--){
			if (tmp >= pw[j + 1]){
				dp[i] += dp[j];
				tmp -= pw[j + 1];
			}
			if (tmp >= maks[j]){
				dp[i] += dp[j];
				tmp = 0;
				break;
			}
		}
		dp[i] += (ll)tmp;
	}

	return dp[m - 1];
}


/*
int main() {
	fileio();
	int q;
	assert(scanf("%d", &q) == 1);
	vector<int> k(q);
	vector<long long> x(q);
	vector<vector<long long>> a(q);
	vector<long long> results(q);
	for (int t = 0; t < q; t++) {
		assert(scanf("%d%lld", &k[t], &x[t]) == 2);
		a[t] = vector<long long>(k[t]);
		for (int i = 0; i < k[t]; i++) {
			assert(scanf("%lld", &a[t][i]) == 1);
		}
	}
	fclose(stdin);

	for (int t = 0; t < q; t++) {
		results[t] = count_tastiness(x[t], a[t]);
	}
	for (int t = 0; t < q; t++) {
		printf("%lld\n", results[t]);
	}
	fclose(stdout);
	return 0;
}

*/

• Subtask 1: 0 / 9
• Subtask 2: 0 / 12
• Subtask 3: 0 / 21
• Subtask 4: 35 / 35
• Subtask 5: 0 / 23