이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl
#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)
template<typename T>
void amin(T &a, T b) {
a = min(a,b);
}
template<typename T>
void amax(T &a, T b) {
a = max(a,b);
}
#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif
/*
read the solution a long time ago, remember some key ideas from there
*/
const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;
const int LOG = 17;
template<typename T>
struct sparse_table {
/*============================*/
T merge(T a, T b) {
return max(a,b);
}
/*============================*/
vector<vector<T>> table;
vector<int> bin_log;
int LOG = 0;
sparse_table() {
}
sparse_table(vector<T> &a, int n) {
while ((1 << LOG) <= n) LOG++;
table = vector<vector<T>>(n, vector<T>(LOG));
bin_log = vector<int>(n + 1);
rep(i, n) table[i][0] = a[i];
rep1(j, LOG - 1) {
rep(i, n) {
int jump = 1 << (j - 1);
if (i + jump >= n) {
break;
}
table[i][j] = merge(table[i][j - 1], table[i + jump][j - 1]);
}
}
bin_log[1] = 0;
for (int i = 2; i <= n; ++i) {
bin_log[i] = bin_log[i / 2] + 1;
}
}
T query(int l, int r) {
int len = r - l + 1;
int k = bin_log[len];
T val1 = table[l][k];
T val2 = table[r - (1 << k) + 1][k];
return merge(val1, val2);
}
};
ll up[N][LOG];
void solve(int test_case)
{
ll n,k; cin >> n >> k;
vector<pll> a(n+5);
rep1(i,n) cin >> a[i].ff >> a[i].ss;
rep1(i,n) a[i].ss--;
auto sa = a;
rep1(i,n) swap(sa[i].ff,sa[i].ss);
sort(sa.begin()+1,sa.begin()+n+1);
set<pll> st;
st.insert({-inf1,-inf1});
st.insert({inf1,inf1});
auto ok = [&](ll l, ll r){
auto it1 = st.lower_bound({l+1,-1});
it1--;
auto it2 = st.lower_bound({r+1,-1});
it2--;
if(it1 != it2) return false;
auto [lx,rx] = *it1;
if((lx <= l and l <= rx) or (lx <= r and r <= rx)) return false;
return true;
};
vector<ll> ls(n+5);
rep1(i,n) ls[i] = sa[i].ss;
sparse_table<ll> sparse(ls,n+1);
auto f = [&](ll lx, ll rx){
ll p = lower_bound(sa.begin()+1,sa.begin()+n+1,pll{lx,-1})-sa.begin();
ll lo = p, hi = n;
ll first = -1;
while(lo <= hi){
ll mid = (lo+hi) >> 1;
if(sparse.query(p,mid) >= lx){
first = mid;
hi = mid-1;
}
else{
lo = mid+1;
}
}
if(first == -1) return 0ll;
if(sa[first].ff > rx) return 0ll;
ll i = first;
ll cnt = 1;
rev(j,LOG-1,0){
auto [r2,l2] = sa[up[i][j]];
if(r2 > rx) conts;
cnt += 1<<j;
i = up[i][j];
}
return cnt;
};
sa[n+1] = {inf1,inf1};
vector<ll> nxt(n+5,n+1);
rev(i,n,1){
auto [r,l] = sa[i];
ll lo = i+1, hi = n;
while(lo <= hi){
ll mid = (lo+hi) >> 1;
if(sparse.query(i+1,mid) > r){
nxt[i] = mid;
hi = mid-1;
}
else{
lo = mid+1;
}
}
}
rep1(i,n+1) up[i][0] = nxt[i];
rep1(j,LOG-1){
rep1(i,n+1){
up[i][j] = up[up[i][j-1]][j-1];
}
}
ll cnt = f(-inf1+1,inf1-1);
if(cnt < k){
cout << -1 << endl;
return;
}
vector<ll> ans;
rep1(i,n){
if(sz(ans) == k) break;
auto [l,r] = a[i];
if(!ok(l,r)) conts;
st.insert({l,r});
auto it = st.find({l,r});
auto [pl,pr] = *prev(it);
auto [nl,nr] = *next(it);
ll curr_cnt = cnt+1;
curr_cnt -= f(pr+1,nl-1);
curr_cnt += f(pr+1,l-1);
curr_cnt += f(r+1,nl-1);
if(curr_cnt >= k){
ans.pb(i);
cnt = curr_cnt;
}
else{
st.erase(it);
}
}
assert(sz(ans) == k);
trav(x,ans) cout << x << endl;
}
int main()
{
fastio;
int t = 1;
// cin >> t;
rep1(i, t) {
solve(i);
}
return 0;
}
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