제출 #1032783

#제출 시각아이디문제언어결과실행 시간메모리
1032783AmirAli_H1통행료 (IOI18_highway)C++17
90 / 100
185 ms15596 KiB
// In the name of Allah #include <bits/stdc++.h> #include "highway.h" using namespace std; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef complex<ld> cld; #define all(x) (x).begin(),(x).end() #define len(x) ((ll) (x).size()) #define F first #define S second #define pb push_back #define sep ' ' #define endl '\n' #define Mp make_pair #define kill(x) cout << x << '\n', exit(0) #define set_dec(x) cout << fixed << setprecision(x); #define file_io(x,y) freopen(x, "r", stdin); freopen(y, "w", stdout); mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int maxn = 2e5 + 4; const int oo = 1e9 + 7; int n, m; ll D; vector<int> adj[maxn], ls; vector<pii> E; bool M[maxn]; int arr[maxn], dis[maxn]; queue<int> qu; void bfs(int v) { fill(dis, dis + n, oo); dis[v] = 0; qu.push(v); while (!qu.empty()) { v = qu.front(); qu.pop(); for (int u : adj[v]) { if (dis[v] + 1 < dis[u]) { dis[u] = dis[v] + 1; qu.push(u); } } } } bool cmp(int i, int j) { return (dis[i] < dis[j]); } ll askx() { ls.clear(); ls.resize(m); for (int i = 0; i < m; i++) { int u = E[i].F, v = E[i].S; if (M[u] || M[v]) ls[i] = 1; else ls[i] = 0; } return ask(ls); } int getv(vector<int> vc) { if (len(vc) == 1) return vc[0]; vector<int> vc1, vc2; int mid = (len(vc) / 2); for (int i = 0; i < mid; i++) vc1.pb(vc[i]); for (int i = mid; i < len(vc); i++) vc2.pb(vc[i]); for (int u : vc1) M[u] = 1; if (askx() == D) return getv(vc2); else { for (int u : vc1) M[u] = 0; return getv(vc1); } } int getx(int R) { iota(arr, arr + n, 0); sort(arr, arr + n, cmp); int l = 0, r = n; if (R != -1) { l = n; r = 0; for (int i = 0; i < n; i++) { if (dis[arr[i]] == R) { l = min(l, i); r = max(r, i + 1); } } } while (r - l > 1) { int mid = (l + r) / 2; for (int j = 0; j < n; j++) { M[arr[j]] = (j >= mid); } if (askx() > D) l = mid; else r = mid; } return arr[l]; } void find_pair(int Nx, vector<int> ux, vector<int> vx, int A, int B) { n = Nx; m = len(ux); for (int i = 0; i < m; i++) { int u = ux[i], v = vx[i]; adj[u].pb(v); adj[v].pb(u); E.pb(Mp(u, v)); } D = askx(); vector<int> vc; for (int i = 0; i < n; i++) { M[i] = 0; vc.pb(i); } int vr = getv(vc); bfs(vr); int u1 = getx(-1); bfs(u1); int u2 = getx(D / A); answer(u1, u2); }
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