oj.uz

답안 #1019096

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1019096 2024-07-10T13:27:56 Z GrindMachine Homecoming (BOI18_homecoming) C++17
31 / 100
 452 ms 262144 KB 
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*

refs:
edi

*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

#include "homecoming.h"

template<typename T>
struct segtree {
    // https://codeforces.com/blog/entry/18051

    /*=======================================================*/

    struct data {
        ll a[2][2];
        data(){
            rep(i,2) rep(j,2) a[i][j] = -inf2;
        }
    };

    data neutral = data();

    data merge(data &left, data &right) {
        data curr;
        
        rep(a,2){
            rep(b,2){
                amax(curr.a[a][b],left.a[a][b]);
                amax(curr.a[a][b],right.a[a][b]);

                rep(c,2){
                    amax(curr.a[a][c],left.a[a][b]+right.a[b][c]);
                }
            }
        }

        return curr;
    }

    void create(int i, T v) {
        auto [x,y] = v;
        tr[i].a[0][0] = max(x+y,0ll);
        tr[i].a[0][1] = x;
        tr[i].a[1][0] = y;
        tr[i].a[1][1] = -inf2;
    }

    void modify(int i, T v) {
        auto [x,y] = v;
        tr[i].a[0][0] = max(x+y,0ll);
        tr[i].a[0][1] = x;
        tr[i].a[1][0] = y;
        tr[i].a[1][1] = -inf2;
    }

    /*=======================================================*/

    int n;
    vector<data> tr;

    segtree() {

    }

    segtree(int siz) {
        init(siz);
    }

    void init(int siz) {
        n = siz;
        tr.assign(2 * n, neutral);
    }

    void build(vector<T> &a, int siz) {
        rep(i, siz) create(i + n, a[i]);
        rev(i, n - 1, 1) tr[i] = merge(tr[i << 1], tr[i << 1 | 1]);
    }

    void pupd(int i, T v) {
        modify(i + n, v);
        for (i = (i + n) >> 1; i; i >>= 1) tr[i] = merge(tr[i << 1], tr[i << 1 | 1]);
    }

    data query(int l, int r) {
        data resl = neutral, resr = neutral;

        for (l += n, r += n; l <= r; l >>= 1, r >>= 1) {
            if (l & 1) resl = merge(resl, tr[l++]);
            if (!(r & 1)) resr = merge(tr[r--], resr);
        }

        return merge(resl, resr);
    }
};

ll solve(int n, int k, int *A, int *B){
    // all subjects win (so all books taken)
    ll all_win = 0;
    rep(i,n) all_win += A[i]-B[i];

    ll ans = max(all_win,0ll);

    segtree<pll> st(2*n);
    ll s = 0, cost2 = 0;
    rep(i,k) s += B[i];
 
    rep(i,2*n){
        if(i+k-1 >= 2*n) break;
        
        if(i){
            s -= B[(i-1)%n];
            s += B[(i+k-1)%n];
        }
 
        ll cost1 = A[i%n]-s;
        cost2 += A[i%n]-B[(i+k-1)%n];
        cost1 -= cost2;
        st.pupd(i,{cost1,cost2});
    }
 
    // at least 1 subject doesnt win (so at least 1 book not taken)
    rep(f,n){
        // f = first book not taken
        ll val = st.query(f+1,f+n-k).a[0][0];
        amax(ans,val);
    }

    return ans;
}

Subtask #1
13.0 / 13.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 344 KB Output is correct
2 Correct 1 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 0 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct

Subtask #2
18.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 344 KB Output is correct
2 Correct 1 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 0 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 2 ms 1116 KB Output is correct
7 Correct 3 ms 1116 KB Output is correct
8 Correct 3 ms 856 KB Output is correct
9 Correct 4 ms 1116 KB Output is correct
10 Correct 2 ms 580 KB Output is correct

Subtask #3
0 / 31.0

# 결과 실행 시간 메모리 Grader output
1 Correct 452 ms 76436 KB Output is correct
2 Correct 15 ms 860 KB Output is correct
3 Runtime error 157 ms 262144 KB Execution killed with signal 9
4 Halted 0 ms 0 KB -

Subtask #4
0 / 38.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 344 KB Output is correct
2 Correct 1 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 0 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 2 ms 1116 KB Output is correct
7 Correct 3 ms 1116 KB Output is correct
8 Correct 3 ms 856 KB Output is correct
9 Correct 4 ms 1116 KB Output is correct
10 Correct 2 ms 580 KB Output is correct
11 Correct 452 ms 76436 KB Output is correct
12 Correct 15 ms 860 KB Output is correct
13 Runtime error 157 ms 262144 KB Execution killed with signal 9
14 Halted 0 ms 0 KB -