#include "doll.h"
//{
#include<bits/stdc++.h>
using namespace std;
typedef int ll;
typedef double lf;
typedef pair<ll,ll> ii;
#define REP(i,n) for(ll i=0;i<n;i++)
#define REP1(i,n) for(ll i=1;i<=n;i++)
#define FILL(i,n) memset(i,n,sizeof i)
#define X first
#define Y second
#define SZ(_a) (int)_a.size()
#define ALL(_a) _a.begin(),_a.end()
#define pb push_back
#ifdef brian
#define debug(...) do{\
fprintf(stderr,"%s - %d (%s) = ",__PRETTY_FUNCTION__,__LINE__,#__VA_ARGS__);\
_do(__VA_ARGS__);\
}while(0)
template<typename T>void _do(T &&_x){cerr<<_x<<endl;}
template<typename T,typename ...S> void _do(T &&_x,S &&..._t){cerr<<_x<<" ,";_do(_t...);}
template<typename _a,typename _b> ostream& operator << (ostream &_s,const pair<_a,_b> &_p){return _s<<"("<<_p.X<<","<<_p.Y<<")";}
template<typename It> ostream& _OUTC(ostream &_s,It _ita,It _itb)
{
_s<<"{";
for(It _it=_ita;_it!=_itb;_it++)
{
_s<<(_it==_ita?"":",")<<*_it;
}
_s<<"}";
return _s;
}
template<typename _a> ostream &operator << (ostream &_s,vector<_a> &_c){return _OUTC(_s,ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s,set<_a> &_c){return _OUTC(_s,ALL(_c));}
template<typename _a,typename _b> ostream &operator << (ostream &_s,map<_a,_b> &_c){return _OUTC(_s,ALL(_c));}
template<typename _t> void pary(_t _a,_t _b){_OUTC(cerr,_a,_b);cerr<<endl;}
#define IOS()
#else
#define debug(...)
#define pary(...)
#define endl '\n'
#define IOS() ios_base::sync_with_stdio(0);cin.tie(0);
#endif // brian
//}
const ll MAXn = 400000 + 5;
ll x[MAXn], y[MAXn];
vector<int> C, X, Y;
ll sit = 0;
ll nnd(){
return --sit;
}
void build(int &now, vector<int> v)
{
debug(v);
if(SZ(v) == 1){
now = v[0];
return;
}
now = nnd();
vector<int> a, b;
if(SZ(v) % 2 != 0){
a.pb(now);
for(int i = 0;i < SZ(v);i += 2)b.pb(v[i]);
for(int i = 1;i < SZ(v);i += 2)a.pb(v[i]);
}else{
for(int i = 0;i < SZ(v);i += 2)a.pb(v[i]);
for(int i = 1;i < SZ(v);i += 2)b.pb(v[i]);
}
assert(SZ(a) == SZ(b));
debug(a, b);
build(x[- now - 1], a);
build(y[- now - 1], b);
}
void create_circuit(int M, std::vector<int> A) {
X.clear();Y.clear();C.clear();sit = 0;
int rt;
A.pb(0);
build(rt, A);
REP(i, M+1)C.pb(rt);
REP(i, -sit)X.pb(x[i]), Y.pb(y[i]);
answer(C, X, Y);
}
