Submission #1010957

#	Time	Username	Problem	Language	Result	Execution time	Memory
1010957		GrindMachine	Raisins (IOI09_raisins)	C++17	100 / 100	416 ms	36292 KiB

raisins

#pragma GCC optimize("O3,unroll-loops")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*



*/

const int MOD = 1e9 + 7;
const int N = 50 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

int a[N][N], p[N][N];
int dp[N][N][N][N];
int n,m;

int f(int r1, int c1, int r2, int c2){
    return p[r2][c2]-p[r1-1][c2]-p[r2][c1-1]+p[r1-1][c1-1];
}

int go(int l1, int r1, int l2, int r2){
    if(l1 > r1 or l2 > r2) return 0;
    int cost = f(l1,l2,r1,r2);
    if(l1 == r1 and l2 == r2) return 0;
    if(dp[l1][r1][l2][r2] != -1) return dp[l1][r1][l2][r2];

    int ans = inf1;
    for(int i = l1; i < r1; ++i){
        amin(ans,go(l1,i,l2,r2)+go(i+1,r1,l2,r2));
    }
    for(int j = l2; j < r2; ++j){
        amin(ans,go(l1,r1,l2,j)+go(l1,r1,j+1,r2));
    }

    ans += cost;
    return dp[l1][r1][l2][r2] = ans;
}

void solve(int test_case)
{
    cin >> n >> m;
    rep1(i,n) rep1(j,m) cin >> a[i][j];
    rep1(i,n) rep1(j,m) p[i][j] = p[i-1][j]+p[i][j-1]-p[i-1][j-1]+a[i][j];
    memset(dp,-1,sizeof dp);
    int ans = go(1,n,1,m);
    cout << ans << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 1: 100 / 100