제출 #1010275

#제출 시각아이디문제언어결과실행 시간메모리
1010275GrindMachinePalembang Bridges (APIO15_bridge)C++17
22 / 100
92 ms16592 KiB
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*



*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

void solve(int test_case)
{
    ll k,n; cin >> k >> n;
    vector<pll> a;
    ll same_side = 0;
    vector<ll> b;
    map<ll,ll> mp;
    ll sum = 0;

    rep1(i,n){
        char p,q; ll x,y;
        cin >> p >> x >> q >> y;
        if(p == q){
            same_side += abs(x-y);
        }
        else{
            if(x > y) swap(x,y);
            a.pb({x,y});
            mp[x]++, mp[y]++;
            sum += x+y;
        }
    }

    mp[-1] = 0;
    ll coeff = -2*sz(a);
    ll ans = inf2;

    for(auto [x,c] : mp){
        coeff += 2*c;
        sum -= 2*x*c;
        amin(ans,coeff*x+sum);
    }

    ans += same_side+sz(a);
    cout << ans << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}
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