제출 #1006415

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1006415		christinelynn	Collecting Mushrooms (NOI18_collectmushrooms)	C++17	0 / 100	1 ms	600 KiB

mushrooms

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define ll long long
#define ld long double
#define pb push_back
#define endl '\n'
#define all(v) v.begin(), v.end()
#define all1(v) v.begin() + 1, v.end()
#define rall(v) v.rbegin(), v.rend()
#define rall1(v) v.rbegin(), v.rend()-1
#define fr(m,n,k) for(int m=n;m<=k;m++)
#define frr(m,n,k) for(int m=n;m>=k;m--)
#define yes cout << "YES"
#define no cout << "NO"
#define yesm cout << "Yes"
#define nom cout << "No"
#define inf 1e18
#define ext {cout << -1; return;}
#define zxt {cout << 0; return;}
#define noxt {no;return;}
#define yesxt {yes;return;}
#define fill(x,s) memset(x, s, sizeof(x));
#define lb lower_bound
#define ub upper_bound
#define pi pair<int,int>
#define vi vector<int>
#define vvi vector<vi>
#define vs vector<string>
#define vpi vector<pi>
#define mii map<int,int>
#define si set<int>
#define fi first
#define se second
#define sz size()
#define el cout << endl

// int mod = 1e9 + 7;
int mod = 998244353;

int ft(int n) {int ans = 1; for (int i = 1; i <= n; ++i) {ans = ans * i;} return ans;}
int binpow(int x, int y) {if (y == 0) return 1; int z = 1; while (y) {  if (y & 1) z = z * x % mod; x = x * x % mod; y >>= 1;} return z;}
int inv(int x) {return binpow(x, mod - 2);}
int bintoint(string s) {reverse(all(s)); int xx = 0; int m = 1; int z = s.sz; fr(j, 0, z) {xx += (s[j] == '1' ? m : 0); m <<= 1;} return xx;}
string inttobin(int x) {if (x == 0) return "0"; string s; while (x) {s += (x & 1) + '0'; x >>= 1;} reverse(all(s)); return s;}
string ads(string s, string p) {if (s.sz > p.sz) swap(s, p); int n = s.sz, m = p.sz; reverse(all(s)); reverse(all(p)); int tm = 0; string st; fr(i, 0, n - 1) {tm = s[i] - '0' + p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} fr(i, n, m - 1) {tm = p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} if (tm != 0) {st += '0' + tm % 10;} reverse(all(st)); return st;}

bool id, id1, id2;
int n, m, k, l, r, a, b, c, d, e, x, y, z, i, j, q, t, o;
int mi = inf, ma, sum, ans, num, tp;
string s, p;

const int N = 3e5 + 5;
mt19937 rng((int) new int);
void solve() {
    cin >> n; vi v(n + 1), w(n + 1);
    int par[n + 1]; memset(par, -1, sizeof(par));
    fr(i, 1, n) cin >> v[i]; fr(i, 1, n) cin >> w[i];

    queue<int>q; q.push(n);
    id = 0;

    si ad; fr(i, 0, n - 1) ad.insert(i);
    while (q.sz) {
        auto x = q.front(); q.pop();
        if (x == 0) {
            id = 1;
            break;
        }
        // cout << x << " ";

        int las = x + w[x];
        while (1) {
            auto y = ad.upper_bound(las - v[las] - 1);
            if (y == ad.end() or * y > las) break;

            if (par[*y] == -1) {
                par[*y] = x;
                ad.erase(y);
                q.push(*y);
            }
        }
    }

    if (!id) {
        cout << -1; return;
    }
    x = 0; vi an;
    while (x != n) {
        an.pb(x); x = par[x];
    }
    reverse(all(an));
    cout << an.sz; el;
    for (auto z : an) cout << z << " ";
}
signed main() {
    ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(0);
    int T = 1;
    // cin >> T;
    for (; T--;) {
        cout << fixed << setprecision(1); solve();
        if (T) cout << endl;
    } return 0;
}
// Tc, angka kecil), No Overthink(trivial tp modified),
// Check Kasus Khusus(1,2,1e18), ganti jd bentuk lain (2 case or etc)
// bedah 1 1 variable yg bisa dicari, cari dari jwbn ke ques

// Sorting : Iterate Greedy (pake data struct) / dp / binser
// Graphs / Tree : DFS / adj / dis[a][b] != dis[a][c] + dis[c][b] / indegree
// Yang keliatan kyk dp : bisa jd brute force doang
// Data Structure : BIT / DSU / Segtree, SparseT / dequeue
// Compression, Line Sweep
// Parity (2 or 3, mod 4..) klo dilakuin 2 kali jadi sama aja -> parity mod 2

/*
brute force, greedy, pref sum, 2pointer, gcd/lcm, even/odd
min/max, binser, bfs/dfs, iterate, multiple/divisor

bipartite graph,bitmasking, sliding window, konstanta
divconquer, djikstra, stack(prev and next smaller)
prefix difference
*/

// tools :
//__lg(x),__builtinpopcount,nextpermutation(), is_sorted / alpha / digit,

• Subtask 1: 0 / 9
• Subtask 2: 0 / 10
• Subtask 3: 0 / 18
• Subtask 4: 0 / 23
• Subtask 5: 0 / 19
• Subtask 6: 0 / 21