이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define ll long long
#define fi first
#define se second
#define endl '\n'
template <typename T>
using ordered_set = tree<T, null_type,less<T>, rb_tree_tag,tree_order_statistics_node_update>;
const ll MOD = 1e9 + 7;
const ll INF = 1e18;
ll n, m, d, s, a[300005], b[300005];
int main(){
ios_base::sync_with_stdio(false); cin.tie(NULL);
ll t = 1;
//cin >> t;
while(t--){
cin >> n >> m >> d >> s;
vector<vector<char>> grid(n + 2, vector<char>(m + 2));
vector<vector<ll>> pref(n + 2, vector<ll>(m + 2));
for(int i = 1; i <= n; i++){
for(int j = 1; j <= m; j++){
cin >> grid[i][j];
pref[i][j] = pref[i - 1][j] + pref[i][j - 1] - pref[i - 1][j - 1] + (grid[i][j] == 'S');
//cout << pref[i][j] << " ";
}
//cout << endl;
}
ll ans = 0;
for(int i = 1; i <= n; i++){
for(int j = 1; j <= m; j++){
if(grid[i][j] == 'M'){
ll d1 = min(d, n - i), d2 = min(d, m - j), D1 = min(d + 1, (ll)i), D2 = min(d + 1, (ll)j);
ll cnt = pref[i + d1][j + d2] - pref[i + d1][j - D2] - pref[i - D1][j + d2] + pref[i - D1][j - D2];
if(cnt >= s) ans++;
}
}
}
cout << ans << endl;
}
return 0;
}
/*
*/
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