제출 #1004168

#제출 시각아이디문제언어결과실행 시간메모리
1004168GrindMachine코알라 (APIO17_koala)C++17
64 / 100
42 ms600 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* read some solutions long time back, remember some ideas from there */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "koala.h" int q = 0; vector<int> query(vector<int> a){ // q++; // assert(q <= 700); int n = sz(a); int arr[n]; rep(i,n) arr[i] = a[i]; int res_arr[n]; playRound(arr,res_arr); vector<int> res(n); rep(i,n) res[i] = res_arr[i]; return res; } int minValue(int n, int w) { // TODO: Implement Subtask 1 solution here. // You may leave this function unmodified if you are not attempting this // subtask. vector<int> a(n); a[0] = 1; auto res = query(a); int pos1 = -1; rep(i,n){ if(!res[i]){ pos1 = i; } } return pos1; } int maxValue(int n, int w) { // TODO: Implement Subtask 2 solution here. // You may leave this function unmodified if you are not attempting this // subtask. vector<int> cands; rep(i,n) cands.pb(i); while(sz(cands) > 1){ int siz = sz(cands); int mx = 2*w-(n-siz); int x = mx/siz-1; vector<int> a(n); trav(i,cands) a[i] = x; auto res = query(a); vector<int> cands2; trav(i,cands){ if(res[i] > x){ cands2.pb(i); } } cands = cands2; } return cands[0]; } int greaterValue(int n, int w) { // TODO: Implement Subtask 3 solution here. // You may leave this function unmodified if you are not attempting this // subtask. int lo = 1, hi = 20; while(lo <= hi){ int mid = (lo+hi) >> 1; vector<int> a(n); a[0] = a[1] = mid-1; auto res = query(a); int pick0 = res[0] > a[0]; int pick1 = res[1] > a[1]; if(pick0^pick1){ if(pick0) return 0; else return 1; } if(!pick0){ hi = mid-1; } else{ lo = mid+1; } } assert(0); return 0; } int n; bool cmp(int i, int j){ // i < j? int lo = 1, hi = 15; while(lo <= hi){ int mid = (lo+hi) >> 1; vector<int> a(n); a[i] = a[j] = mid-1; // rep(i,n){ // a[i] = (a[i]+1)*2-1; // } auto res = query(a); int pick0 = res[i] > a[i]; int pick1 = res[j] > a[j]; if(pick0^pick1){ if(pick0) return false; else return true; } if(!pick0){ hi = mid-1; } else{ lo = mid+1; } } assert(0); return false; } void allValues(int n_, int w, int *ans) { n = n_; if (w == 2*n) { // TODO: Implement Subtask 4 solution here. // You may leave this block unmodified if you are not attempting this // subtask. q = 0; // vector<int> sa(n); // iota(all(sa),0); // stable_sort(all(sa),cmp); vector<int> a(n,2); auto res = query(a); vector<int> small,big; rep(i,n){ if(res[i] > a[i]){ big.pb(i); } else{ small.pb(i); } } stable_sort(all(small),cmp); stable_sort(all(big),cmp); auto sa = small; trav(x,big) sa.pb(x); rep(i,n) ans[sa[i]] = i+1; } else { // TODO: Implement Subtask 5 solution here. // You may leave this block unmodified if you are not attempting this // subtask. vector<int> a(n,1); auto res = query(a); vector<int> small,big; rep(i,n){ if(res[i] > a[i]){ big.pb(i); } else{ small.pb(i); } } stable_sort(all(small),cmp); stable_sort(all(big),cmp); auto sa = small; trav(x,big) sa.pb(x); rep(i,n) ans[sa[i]] = i+1; // vector<int> a(n); // iota(all(a),0); // stable_sort(all(a),cmp); // rep(i,n) ans[a[i]] = i+1; } }
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