제출 #1001016

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1001016		GrindMachine	Red-blue table (IZhO19_stones)	C++17	100 / 100	72 ms	3412 KiB

stones

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*

read some accepted submissions a long time ago, didnt understand the idea behind them back then
when trying again, realized that we could fix the #of ignored rows and cols, take the best grid over all possible options instead of doing casework

*/

const int MOD = 1e9 + 7;
const int N = 1e3 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

char a[N][N], ans[N][N];

void solve(int test_case)
{
    int n,m; cin >> n >> m;
    int best = -inf1;

    auto go = [&](){
        int cost = 0;

        rep1(i,n){
            int cnt = 0;
            rep1(j,m){
                if(a[i][j] == 'x') cnt++;
            }
            if(cnt > m/2) cost++;
        }

        rep1(j,m){
            int cnt = 0;
            rep1(i,n){
                if(a[i][j] == '.') cnt++;
            }
            if(cnt > n/2) cost++;
        }

        if(cost > best){
            best = cost;
            rep1(i,n) rep1(j,m) ans[i][j] = a[i][j];
        }
    };

    rep(ignore_rows,min(n+1,5)){
        rep(ignore_cols,min(m+1,5)){
            rep1(i,n) rep1(j,m) a[i][j] = '.';
            int ptr = 1;
            rep1(i,n-ignore_rows){
                for(int j = m-ignore_cols+1; j <= m; ++j){
                    a[i][j] = 'x';
                }
                int need = (m/2+1)-ignore_cols;
                while(need >= 1){
                    a[i][ptr] = 'x';
                    need--;
                    ptr++;
                    if(ptr >= m-ignore_cols+1) ptr = 1;
                }
            }

            go();
        }
    }   

    cout << best << endl;
    rep1(i,n){
        rep1(j,m){
            if(ans[i][j] == 'x') cout << '+';
            else cout << '-'; 
        }
        cout << endl;
    }
}

int main()
{
    fastio;

    int t = 1;
    cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 1: 17 / 17
• Subtask 2: 10 / 10
• Subtask 3: 16 / 16
• Subtask 4: 11 / 11
• Subtask 5: 15 / 15
• Subtask 6: 31 / 31