이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define db long double
#define ii pair<int, int>
#define fi first
#define se second
const int maxn = 3e5+5;
const ll mod = 111539786;
const db eps = -1e9;
const ll inf = 1e18;
int n, k;
int a[maxn];
ll dp[2005][2005];
ll s[maxn];
struct sub1{
ll sum = 0;
void solve(){
for(int i=1; i<=n; i++){
sum += a[i];
}
cout << sum << "\n";
}
} s1;
struct sub2{
void solve(){
int pos = 0;
for(int i=1; i<=n; i++){
if(a[i] < 0) pos = i;
}
ll sum1 = 0, sum2 = 0;
for(int i=1; i<pos; i++){
sum1 += a[i];
}
for(int i=pos+1; i<=n; i++){
sum2 += a[i];
}
if(k == 1) cout << max({sum1, sum2, sum1+sum2+a[pos]});
else{
cout << sum1 + sum2 << "\n";
}
}
} s2;
struct sub3{
void solve(){
ll min_val = 0;
ll ans = 0;
for(int i=1; i<=n; i++){
ans = max(ans, s[i] - min_val);
min_val = min(min_val, s[i]);
}
cout << ans << "\n";
}
} s3;
struct sub4{
void solve(){
for(int i=1; i<=k; i++){
ll max_val = 0;
for(int j=1; j<=n; j++){
dp[i][j] = dp[i][j-1];
dp[i][j] = max(dp[i][j], max_val + s[j]);
max_val = max(max_val, dp[i-1][j] - s[j]);
}
}
cout << dp[k][n] << "\n";
}
} s4;
bool checks1(){
int min_val = a[1];
for(int i=2; i<=n; i++){
min_val = min(min_val, a[i]);
}
return min_val >= 0;
}
bool checks2(){
int cnt = 0;
for(int i=1; i<=n; i++){
if(a[i] < 0) cnt++;
}
return cnt <= 1;
}
bool checks3(){
return k == 1;
}
void solve(){
cin >> n >> k;
for(int i=1; i<=n; i++){
cin >> a[i];
s[i] = s[i-1] + a[i];
}
if(checks1()) s1.solve();
else if(checks2()) s2.solve();
else if(checks3()) s3.solve();
else s4.solve();
}
int main(){
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int test = 1;
while(test--){
solve();
}
}
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