Submission #999407

#TimeUsernameProblemLanguageResultExecution timeMemory
999407AdiKnapsack (NOI18_knapsack)C++17
12 / 100
16 ms31912 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; using namespace std; template <class T> using indexed_set=tree<int,null_type,less<int>,rb_tree_tag, tree_order_statistics_node_update>; const long long M = 1000000007; #define multiply(a,b) ((a % M ) * (b % M)) % M #define all(a) (a).begin(), (a).end() #define ll long long #define ld long double #define max(a,b)( a > b ? a : b ) #define loop(i,a,b) for(long long i=a;i<b;i++) #define rloop(i,a,b) for(int i=a;i>=b;i--) #define logarr(arr,a,b) for(int i=a;i<b;i++) cout<<arr[i]<<" "; cout<<endl #define vi vector<int> #define pi pair<int,int> #define f first #define s second #define pb push_back #define pob pop_back #define p push #define po pop #define gcd(a,b) __gcd(a,b) #define yes "YES\n" #define no "NO\n" // find_by_order -> iterator to value // order_of_key -> index where value is/will be long long binary_expo(long long x, long long n) { if (n == 0) return 1; if (n == 1) return x % M; long long temp = binary_expo(x, n / 2); temp = multiply(temp, temp); if (n % 2) temp = multiply(temp, x); return temp; } signed main(){ ios::sync_with_stdio(false);cin.tie(NULL); ll n,s; cin>>s>>n; vector<priority_queue<pair<ll,ll>>>trk(s+1); ll x,y,z; loop(i,0,n){ cin>>x>>y>>z; trk[y].push(make_pair(x,z)); } vector<vector<ll>> dp(s+1,vector<ll>(s+1,LLONG_MIN)); ll p=-1; vector<pair<ll,ll>> vec; for(ll ind = 1; ind<=s;ind++){ dp[ind][0]=0; if( trk[ind].empty() ) continue; if( p == -1 ){ //base case ..... ll sum=0,prof=0; while( !trk[ind].empty() ){ ll val =trk[ind].top().first; ll time= trk[ind].top().second; trk[ind].pop(); prof+=val; sum+=ind; while( time-- && sum <=s ){ dp[ind][sum]=prof; prof+=(val); sum+=(ind); } prof-=val; sum-=ind; } } else{ int sz=trk[ind].size(); vec.resize(sz); int x=0; while( !trk[ind].empty() ){ vec[x]=(trk[ind].top()); x++; trk[ind].pop(); } for(ll sum=0;sum<=s;sum++){ ll notake = dp[p][sum]; ll take = LLONG_MIN; ll sm = 0,prof=0,i=0; while( i < sz && sum - sm >=0 ){ ll val =vec[i].first; ll time=vec[i].second; prof+=val; sm+=ind; while( time-- && sum - sm >= 0 ){ if( dp[p][ sum - sm ] != LLONG_MIN ){ take=max(take,prof+dp[p][sum-sm]); } prof+=val; sm+=ind; } i++; } dp[ind][sum]=max(notake,take); } } p=ind; } ll maxprof=0; for(ll i=0;i<=s;i++){ if( dp[p][i] != LLONG_MIN)maxprof=max(maxprof,dp[p][i]); } std::cout<<maxprof<<endl; return 0; }
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