이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define x first
#define y second
using namespace std;
typedef long long ll;
typedef pair<int, int> p;
const int mod = 1e9;
const int dx[] = {1, -1, 0, 0};
const int dy[] = {0, 0, 1, -1};
int size[101010];
int chk[101010];
int n;
map<p, int> mp;
set<int> g[101010];
void dfs(int now, int prv, ll &dist){
for(auto nxt : g[now]){
if(nxt ^ prv && !chk[nxt]){
chk[nxt] = 1;
dfs(nxt, now, dist);
size[now] += size[nxt];
}
}
ll tmp = (ll)size[now] * (ll)(n - size[now]);
tmp %= mod;
dist += tmp; dist %= mod;
}
ll getDist(){
ll ret = 0;
chk[1] = 1;
dfs(1, 0, ret);
return ret;
}
void makeTree(vector<p> &v){
sort(v.begin()+1, v.end());
memset(size, 0, sizeof size);
memset(chk, 0, sizeof chk);
for(int i=0; i<=n; i++) g[i].clear();
mp.clear();
int cnt = 1;
mp[v[1]] = cnt;
size[cnt]++;
for(int i=2; i<=n; i++){
if(v[i-1].x == v[i].x && v[i-1].y+1 == v[i].y){
mp[v[i]] = cnt;
}
else mp[v[i]] = ++cnt;
size[cnt]++;
}
for(int i=1; i<=n; i++){
int x = v[i].x, y = v[i].y;
int now = mp[v[i]];
for(int k=0; k<4; k++){
int xx = x + dx[k];
int yy = y + dy[k];
int nxt = mp[{xx, yy}];
if(nxt && now != nxt) g[now].insert(nxt);
}
}
}
int DistanceSum(int N, int *X, int *Y){
n = N;
ll ret = 0;
vector<p> v(n+1);
for(int i=0; i<n; i++){
v[i+1] = {X[i], Y[i]};
}
makeTree(v);
ret += getDist() % mod;
for(int i=0; i<n; i++){
v[i+1] = {Y[i], X[i]};
}
makeTree(v);
ret += getDist() % mod;
ret %= mod;
return (int)ret;
}
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