Submission #998602

#TimeUsernameProblemLanguageResultExecution timeMemory
998602GrindMachine"The Lyuboyn" code (IZhO19_lyuboyn)C++17
8 / 100
1 ms604 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(...) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,k,t; cin >> n >> k >> t; string s; cin >> s; if(!(k&1)){ cout << -1 << endl; return; } vector<string> ans = { "0000","1101","0011","1110", "0101","1011","0110","1000", "1111","0010","1100","0001", "1010","0100","1001","0111" }; rep(i,sz(ans)-1){ string x = ans[i], y = ans[i+1]; ll diff = 0; rep(j,sz(x)){ diff += x[j]!=y[j]; } assert(diff == k); } cout << (1<<n) << endl; trav(x,ans) cout << x << endl; /* ll n = 8, k = 2; vector<ll> a(n); iota(all(a),0); do{ bool ok = true; rep(i,n-1){ ll xo = a[i]^a[i+1]; if(setbits(xo) != k){ ok = false; break; } } if(ok){ debug(a); } } while(next_permutation(all(a))); */ } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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