제출 #998346

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
998346		mispertion	Foehn Phenomena (JOI17_foehn_phenomena)	C++14	100 / 100	87 ms	7336 KiB

foehn_phenomena

#include<bits/stdc++.h>

using namespace std;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
#define int ll
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define pb push_back
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define mispertion ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#define F first
#define S second
#define getlast(s) (*s.rbegin())
#define debg cout << "OK\n"

const ld PI = 3.1415926535;
const int N = 2e5+10;
const int M = 7e6 + 1;
int mod = 998244353;
const int infi = INT_MAX;
const ll infl = LLONG_MAX;
const int P = 2;

int mult(int a, int b) {
    a %= mod;
    b %= mod;
    return a * 1LL * b % mod;
}

int sum(int a, int b) { 
    a %= mod;
    b %= mod;
    if (a + b < 0)
        return a + b + mod;
    if (a + b >= mod)
        return a + b - mod;
    return a + b;
}

ll binpow(ll a, ll n, ll mod) {
    if (n == 0)
        return 1;
    if (n % 2 == 1) {
        return binpow(a, n - 1, mod) * a % mod;
    } else {
        ll b = binpow(a, n / 2, mod);
        return b * b % mod;
    }
}

int n, q, s, t, a[N], d[N], sm = 0;

void solve(){
    cin >> n >> q >> s >> t;
    for(int i = 0; i <= n; i++){
        cin >> a[i];
        if(i > 0)
            d[i] = a[i] - a[i - 1];
        if(d[i] > 0)
            sm -= s * d[i];
        else
            sm -= t * d[i];
    }
    for(int j = 1; j <= q; j++){
        int l, r, x;
        cin >> l >> r >> x;
        if(d[l] > 0)
            sm += s * d[l];
        else
            sm += t * d[l];
        d[l] += x;
        if(d[l] > 0)
            sm -= s * d[l];
        else
            sm -= t * d[l];
        if(r + 1 <= n){
            if(d[r + 1] > 0)
            sm += s * d[r + 1];
        else
            sm += t * d[r + 1];
        d[r + 1] -= x;
        if(d[r + 1] > 0)
            sm -= s * d[r + 1];
        else
            sm -= t * d[r + 1];
        }
    
        cout << sm << '\n';
    }
}   

signed main() {
    mispertion;
    int t = 1;
    //cin >> t;
    while(t--){
        solve();
    }
    return 0;
}

• Subtask 1: 30 / 30
• Subtask 2: 10 / 10
• Subtask 3: 60 / 60